18. By mixing 1.00-mol benzoic acid (C6H5COOH), K₂= 6.3 x 10-¹) and 1.00-mol methylamine (CH3NH₂, K = 5.6 x 10-4) into1-L solution, the solution pH at equilibrium will bea) greater than 7b) equal to 7c) less than 7d) insufficient information.

Answered: Image /qna-images/answer/962a38ee-9b95-4ee0-8b7a-b594a07f28b5.jpg

18. By mixing 1.00-mol benzoic acid (CH-COOH), K₂= 6.3 x 10s) and 1.00-mol methylamine (CH3NH₂, K₂ = 5.6 x 10-4) into 1-L solution, the solution pH at equilibrium will be a) greater than 7 b) equal to 7 c) less than 7 d) insufficient information.

18. By mixing 1.00-mol benzoic acid (CH-COOH), K₂= 6.3 x 10s) and 1.00-mol methylamine (CH3NH₂, K₂ = 5.6 x 10-4) into 1-L solution, the solution pH at equilibrium will be a) greater than 7 b) equal to 7 c) less than 7 d) insufficient information.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.39QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

18. By mixing 1.00-mol benzoic acid (C6H5COOH), K₂= 6.3 x 10-¹) and 1.00-mol methylamine (CH3NH₂, K = 5.6 x 10-4) into
1-L solution, the solution pH at equilibrium will be
a) greater than 7
b) equal to 7
c) less than 7
d) insufficient information.

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Step 1: Write the reactions involved when benzoic and methylamine dissolved in water

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