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19. Decomposition of Sucrose Reacting with water in an acidic solution at 35°C, sucrose (C12H22011) decomposes into glucose (CH1,0,) and fructose (C,H1,0,)* according to the law of uninhibited decay. An initial amount of 0.40 mole of sucrose decomposes to 0.36 mole in 30 minutes. How much sucrose will remain after 2 hours? How long will it take until 0.10 mole of sucrose remains?

19. Decomposition of Sucrose Reacting with water in an acidic solution at 35°C, sucrose (C12H22011) decomposes into glucose (CH1,0,) and fructose (C,H1,0,)* according to the law of uninhibited decay. An initial amount of 0.40 mole of sucrose decomposes to 0.36 mole in 30 minutes. How much sucrose will remain after 2 hours? How long will it take until 0.10 mole of sucrose remains?

Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Chapter10: Radioactivity And Nuclear Processes
Section: Chapter Questions
Problem 10.80E
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19. Decomposition of Sucrose Reacting with water in an acidic solution at 35°C, sucrose (C12H22011) decomposes into glucose (CH1,0,) and fructose (C,H1,0,)* according to the law of uninhibited decay. An initial amount of 0.40 mole of sucrose decomposes to 0.36 mole in 30 minutes. How much sucrose will remain after 2 hours? How long will it take until 0.10 mole of sucrose remains?
Transcribed Image Text:19. Decomposition of Sucrose Reacting with water in an acidic solution at 35°C, sucrose (C12H22011) decomposes into glucose (CH1,0,) and fructose (C,H1,0,)* according to the law of uninhibited decay. An initial amount of 0.40 mole of sucrose decomposes to 0.36 mole in 30 minutes. How much sucrose will remain after 2 hours? How long will it take until 0.10 mole of sucrose remains?
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