1o₂ = 2 · (² x (+) · cos (nwot) at O 11 2 1 = 2 25+ (1-1) cos (2nrrt) dt = 21- - [² (1-t) d 2 Los (n 2πrt) dt (t-1) Sin (2nit) 2n 411 n L Los (21th) 47 n 11 Cos (2nItt) 1 47 n O How did he get the value inside the circle

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