Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.5: Rational Functions
Problem 53E
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Question
Chapter 3 Derivatives
83
Thus
Thus, tanx+ cotx-
Example 9: Suppose that f(0) --3 and f(x)55 for all values of x. How large can f(2) possibly be?
Solution: Suppose that
f(x) 55
This implies f is differentiable (and therefore is continuous) everywhere.
f(0) --3
and
for all values of x.
In particular, we choose f is defined on [0, 2]. Then by Mean Value Theorem on (0, 2], there
exists a number c in (0, 2) such that
f(2) – f(0) _ f2)*
f'(c) =
2-0
- f(2) = 2f'(c) – 3< 2(5) - 3 = 10-3 =7.
This shows the largest possible value for f(2) is 7.
Exercise 3.6
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given
interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem.
1.
a. f(x) = 5 – 12x + 3x², in [1, 3]
b. f(x) = x³ – x² – 6x + 2, in [0, 3]
c. f(x) = cos 2x, in [n/8, 7n/8]
Let f(x) = 1 - x2/3, Show that f(-1) = f(1) but there is no number c in (-1, 1) such that f'(c) = 0.
Why does this not contradict Rolle's Theorem?
2.
3.
Let f(x) = tanx. Show that f(0) = f(T) but there is no number c in (0, t) such that f'(c) = 0. Why
does this not contradict Rolle's Theorem?
Verify that the function satisfies the three hypotheses the Mean Value Theorem on the given
interval. Then find all numbers c that satisfy the conclusion of the Mean Value Theorem.
4.
a. f(x) = 2x² – 3x + 1, in [0, 2].
b. f(x) = x³ + x -1 [0, 2]
C f(x) =e-2, in [0, 3]
d. f(x) =+2 in [1, 4).
Let f(x) = (x - 3)-2. Show that there is no value of c in (1, 4) such that f(4) – f(1) = f'(c) (4 – 1).
Why does this not contradict the Mean Value Theorem?
6.
Show that the equation x3 - 15x + c = 0 has at most one root in the interval [-2, 2].
7. If f(1) = 10 and f'(x) 2 for 1<x<4, how small can f(4) possibly be?
8.
Use the Mean Value Theorem to prove the inequality sina - sinb| < la -b|for all a and b.
9.
Use the method of Example 3 to prove the identity 2 sin-lx = cos-'(1 – 2x²) for x 2 0.
43)
5ha)d
ne theoremn G Soie
Heror de
(0.3) Surh hat
(3) - )
%3D
3-
-2
Heorem t ver1d
Given funetlon s $m)= Cocen
polynomi al funeton Is
= -2 sine
Teal n and
Transcribed Image Text:Chapter 3 Derivatives 83 Thus Thus, tanx+ cotx- Example 9: Suppose that f(0) --3 and f(x)55 for all values of x. How large can f(2) possibly be? Solution: Suppose that f(x) 55 This implies f is differentiable (and therefore is continuous) everywhere. f(0) --3 and for all values of x. In particular, we choose f is defined on [0, 2]. Then by Mean Value Theorem on (0, 2], there exists a number c in (0, 2) such that f(2) – f(0) _ f2)* f'(c) = 2-0 - f(2) = 2f'(c) – 3< 2(5) - 3 = 10-3 =7. This shows the largest possible value for f(2) is 7. Exercise 3.6 Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. 1. a. f(x) = 5 – 12x + 3x², in [1, 3] b. f(x) = x³ – x² – 6x + 2, in [0, 3] c. f(x) = cos 2x, in [n/8, 7n/8] Let f(x) = 1 - x2/3, Show that f(-1) = f(1) but there is no number c in (-1, 1) such that f'(c) = 0. Why does this not contradict Rolle's Theorem? 2. 3. Let f(x) = tanx. Show that f(0) = f(T) but there is no number c in (0, t) such that f'(c) = 0. Why does this not contradict Rolle's Theorem? Verify that the function satisfies the three hypotheses the Mean Value Theorem on the given interval. Then find all numbers c that satisfy the conclusion of the Mean Value Theorem. 4. a. f(x) = 2x² – 3x + 1, in [0, 2]. b. f(x) = x³ + x -1 [0, 2] C f(x) =e-2, in [0, 3] d. f(x) =+2 in [1, 4). Let f(x) = (x - 3)-2. Show that there is no value of c in (1, 4) such that f(4) – f(1) = f'(c) (4 – 1). Why does this not contradict the Mean Value Theorem? 6. Show that the equation x3 - 15x + c = 0 has at most one root in the interval [-2, 2]. 7. If f(1) = 10 and f'(x) 2 for 1<x<4, how small can f(4) possibly be? 8. Use the Mean Value Theorem to prove the inequality sina - sinb| < la -b|for all a and b. 9. Use the method of Example 3 to prove the identity 2 sin-lx = cos-'(1 – 2x²) for x 2 0. 43) 5ha)d ne theoremn G Soie Heror de (0.3) Surh hat (3) - ) %3D 3- -2 Heorem t ver1d Given funetlon s $m)= Cocen polynomi al funeton Is = -2 sine Teal n and
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