Step by step on how to solve redox in acid for question number 6 please lost.reactions and cancel identical species.at atoms and charge are balanced.g equations in acid:which species is being oxidized and which species is being reduced. Write separate half- reacticelements except oxygen and hydrogen.ygen using water.drogen using H.arge using electrons.Electrons gained=Electrons lost. It may be necessary to multiply the half reactions by an inteelectrons gained = electrons lost.actions and cancel identical species.atoms and charge are balanced.Example:13 + Cl²base:3+→MnO4 + Fe Fe³+ + Mn²+4 → Br₂ + Mn²*Cu²+ + NO4. As₂O3 + NO3 → H3ASO4 + NO2-3+5. Cr₂0² + Cl → Cr³+ + Cl₂3+6. Mn²+ + NaBiO3 → Bi³+ + MnO4-ions as if they were in acid.to the number of protons added to each side of the equation.nd OH to make water.ectrons gained=Electrons lost. It may be necessary to multiply the half reactions by arctrons gained = electrons lost.ons and cancel identical species.ms and charge are balanced.

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Answered: 2+ 3+ 6. Mn²+ + NaBiO; → Bi³+ + MnO4-

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2+ 3+ 6. Mn²+ + NaBiO; → Bi³+ + MnO4-

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter6: Chemical Reactions: An Introduction

Section: Chapter Questions

Problem 68AP

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Question

Step by step on how to solve redox in acid for question number 6 please

lost.
reactions and cancel identical species.
at atoms and charge are balanced.
g equations in acid:
which species is being oxidized and which species is being reduced. Write separate half- reactic
elements except oxygen and hydrogen.
ygen using water.
drogen using H.
arge using electrons.
Electrons gained=Electrons lost. It may be necessary to multiply the half reactions by an inte
electrons gained = electrons lost.
actions and cancel identical species.
atoms and charge are balanced.
Example:
13 + Cl²
base:
3+
→
MnO4 + Fe Fe³+ + Mn²+
4 → Br₂ + Mn²*
Cu²+ + NO
4. As₂O3 + NO3 → H3ASO4 + NO
2-
3+
5. Cr₂0² + Cl → Cr³+ + Cl₂
3+
6. Mn²+ + NaBiO3 → Bi³+ + MnO4-
ions as if they were in acid.
to the number of protons added to each side of the equation.
nd OH to make water.
ectrons gained=Electrons lost. It may be necessary to multiply the half reactions by ar
ctrons gained = electrons lost.
ons and cancel identical species.
ms and charge are balanced.

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