2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС() — НСІ (aq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) → 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole

Chemistry by OpenStax (2015-05-04)
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How do I, using Hess’s law and the data below, calculate the ∆H/mole for the reaction?
2 Al(s) + 3 Cl2 (g)
2 AICI:(s)
2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g)
AH = -1049 kJ/mole
HС(9) — НСІ (аq)
AH = -74.8 kJ/mole
H2 (g) + Cl2(g) –→ 2 HCI (g)
AH = -184.5 kJ/mole
AICI3 (s) →AICI3 (aq)
AH = -323 kJ/mole
Transcribed Image Text:2 Al(s) + 3 Cl2 (g) 2 AICI:(s) 2 Al(s) + 6 HCI(aq) → 2 AICI3(aq) + 3 H2 (g) AH = -1049 kJ/mole HС(9) — НСІ (аq) AH = -74.8 kJ/mole H2 (g) + Cl2(g) –→ 2 HCI (g) AH = -184.5 kJ/mole AICI3 (s) →AICI3 (aq) AH = -323 kJ/mole
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