2 Al(s) + 6 HCl(aq)  →  2 AlCl3(aq) + 3 H2(g) According to the equation above, what mass of aluminum is needed to completely react with 3.50 mol of hydrochloric acid?

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Chapter5: Stoichiometry
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2 Al(s) + 6 HCl(aq)  →  2 AlCl3(aq) + 3 H2(g)

According to the equation above, what mass of aluminum is needed to completely react with 3.50 mol of hydrochloric acid?

 

Note: Round off your answer to two decimal places and no need for the units.

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