2) Calculate AH for the reaction: 2N2H4(1) + 202(g) → 2N2(g) + 4H2O(1) given the following data:2NH3(g) + 3N20(g) → 4N2(g) + 3H20(1); AH = -1010 kJN20(g) + 3H2(g) → N2H«(1) + H2O(1); AH = -317 kJ2NH3(g) + ½O2(g) → N2H«(I) + H2O(I); AH = -143 kJH2(g) + ½O2(g) → H2O(1); AH = -286 kJ

Given that : We have to calculate the ∆H for the given reaction : We have to use the below given…

2) Calculate AH for the reaction: 2N;H,(1) + 202(g) → 2N2(g) + 4H2O(1I) given the following data: 2NH3(g) + 3N½O(g) → 4N2(g) + 3H20(1); AH = -1010 kJ N20(g) + 3H2(8) → N2H«(I) + H20(1); AH = -317 kJ 2NH3(g) + ½Oz(g) → N2H«(l) + H2O(1); AH = -143 kJ H2(8) + ¼O2(g) → H2O(1); AH = -286 kJ

2) Calculate AH for the reaction: 2N;H,(1) + 202(g) → 2N2(g) + 4H2O(1I) given the following data: 2NH3(g) + 3N½O(g) → 4N2(g) + 3H20(1); AH = -1010 kJ N20(g) + 3H2(8) → N2H«(I) + H20(1); AH = -317 kJ 2NH3(g) + ½Oz(g) → N2H«(l) + H2O(1); AH = -143 kJ H2(8) + ¼O2(g) → H2O(1); AH = -286 kJ

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter16: Thermodynamics: Directionality Of Chemical Reactions

Section: Chapter Questions

Problem 39QRT

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