66. Calculate AH°for the process Co304(s)3Co(8)+2O2(g) from the following information: Co(s) + O2 (g) → CoO(s) 3C00(s) + ½ O2 (g) → Co3O4 AH*298 =-237.9 kJ AH 298 -177.5 kJ

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Chapter16: Thermodynamics
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Chem Hw need help with question 66 and question 68
66. Calculate AH®for the process Co304(s)3Co(s)+202(g)
from the following information:
Co(s) + % O2 (g) → CoO(s)
3C0O(s) + ½ O2 (g) → Co3O4
AH 298 =-237.9 kJ
AH298 =-177.5 kJ
Solution
Reverse the directions of the two equations so that Co3O4(s) will be on the left-hand side and
multiply the first equation by 3:
addition of the two resulting equation gives:
68. Using the data in Appendix G, calculate the standard enthalpy change for each of the
following reactions:
(a) N2(g)+O2(g)–2NO(g)
(b) Si(s)+2C12(g)→SİC14(g)
(c) Fe203(s)+3H2(g)→2FE(s)+3H2O(1)
(d) 2LİOH(s)+CO2(g)→Lİ2CO3(s)+H2O(g)
Solution
(a)
the reaction of formation of NO(g).
the reaction is twice
(b) This reaction is the reaction of formation of SICL(g); thus, its enthalpy is the enthalpy of
formation of SIC14(g), which is -662.75 (from Appendix G),
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Transcribed Image Text:66. Calculate AH®for the process Co304(s)3Co(s)+202(g) from the following information: Co(s) + % O2 (g) → CoO(s) 3C0O(s) + ½ O2 (g) → Co3O4 AH 298 =-237.9 kJ AH298 =-177.5 kJ Solution Reverse the directions of the two equations so that Co3O4(s) will be on the left-hand side and multiply the first equation by 3: addition of the two resulting equation gives: 68. Using the data in Appendix G, calculate the standard enthalpy change for each of the following reactions: (a) N2(g)+O2(g)–2NO(g) (b) Si(s)+2C12(g)→SİC14(g) (c) Fe203(s)+3H2(g)→2FE(s)+3H2O(1) (d) 2LİOH(s)+CO2(g)→Lİ2CO3(s)+H2O(g) Solution (a) the reaction of formation of NO(g). the reaction is twice (b) This reaction is the reaction of formation of SICL(g); thus, its enthalpy is the enthalpy of formation of SIC14(g), which is -662.75 (from Appendix G), MacBook Air
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