2) Consider the hanging sign shown here (mass of the sign is 5 kg, length of the horizontal bar = 5 meters, with a tension cable connected at the 4 meter mark – the bar has a mass of 2 kg). a) Calculate the tension in the cable (in N). b) Calculate the horizontal force (and direction) at the left connection point (the bolt/hinge). c) Calculate the vertical force (and direction) at the left connection point (the bolt/hinge). 5.0 m 3.0 m 1.0 m 4.0 m GAS ml = 2 kg a) pivot at left end: 0 = tan = 36.87° T sin 0(4m)= (2)(9.8)(2.5m)+(5)(9.8)(5) Tsin0= 73.5N T=122.5N =T cos 0 = (122.5)cos 36.87 =98N b) Fwall m2 = 5 kg c) F, +T sin 0 = m,g+m,g F = (7)(9.8)– 73.5=-4.9N (this means the vertical force is actually pulling down on the left end!)

2) Consider the hanging sign shown here (mass of the sign is 5 kg, length of the horizontal bar = 5 meters, with a tension cable connected at the 4 meter mark – the bar has a mass of 2 kg). a) Calculate the tension in the cable (in N). b) Calculate the horizontal force (and direction) at the left connection point (the bolt/hinge). c) Calculate the vertical force (and direction) at the left connection point (the bolt/hinge). 5.0 m 3.0 m 1.0 m 4.0 m GAS ml = 2 kg a) pivot at left end: 0 = tan = 36.87° T sin 0(4m)= (2)(9.8)(2.5m)+(5)(9.8)(5) Tsin0= 73.5N T=122.5N =T cos 0 = (122.5)cos 36.87 =98N b) Fwall m2 = 5 kg c) F, +T sin 0 = m,g+m,g F = (7)(9.8)– 73.5=-4.9N (this means the vertical force is actually pulling down on the left end!)

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 35P: A uniform 40.0-kg scaffold of length 60 m is supported by tow light cables below. An 80.0 kg painter...

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