2 m 1m-- 2 m This is not your opproperty so do Orsin any www 37 1.5 m your 1.5 s In the assembly shown, sags of s and 1.5 s resulted when the two cylinders were suspended from the rings at A and B, respectively. If s=0 when the cylinders are removed, determine the following: a. the horizontal distance x (mm) moved by point B b. the mass (kg) of the two cylinders C. the forces in the two springs www

2 m 1m-- 2 m This is not your opproperty so do Orsin any www 37 1.5 m your 1.5 s In the assembly shown, sags of s and 1.5 s resulted when the two cylinders were suspended from the rings at A and B, respectively. If s=0 when the cylinders are removed, determine the following: a. the horizontal distance x (mm) moved by point B b. the mass (kg) of the two cylinders C. the forces in the two springs www

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter10: Virtual Work And Potential Energy

Section: Chapter Questions

Problem 10.51P: The spring attached to the homogenous bar of weight W is undeformed when =0. Determine the smallest...

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The spring attached to the homogenous bar of weight W is undeformed when =0. Determine the smallest spring stiffness k for which the =0 equilibrium position will be stable. Use W = 10 lb, a = 24 in., and b = 6 in. Assume that the spring remains horizontal, which is a valid approximation if is small.
Find the stable equilibrium position of the system described in Prob. 10.56 if m = 2.06 kg.
The layout shown is a representation of a machine shop. Components 1 and 2 have masses of m1=265kg and m2=220kg , respectively. Component 3 must be treated as a distributed load, which is w=175 kg/m2 , determined by the area of contact between the component and the shop floor. The dimensions shown have been measured to be a=0.600 m , b=2.00 m , c=1.60 m , d=0.650 m , e=3.10 m , and f=1.10 m . These dimensions represent the x and y components of the locations of the centers of gravity for the respective components. Component 3 has x,y cross-sectional dimensions of x3=1.30 m and y3=0.250 m . Assume the components experience uniform weight distribution in all principle directions. The dimensions a through f locate the centroid of the respective component from the y−z plane and x−z plane.(Figure 1) Part A - The x Component of the Center of Gravity of All the Components Determine the x component of the center of gravity of all the components. Express your answer to three significant…
An athlete of 60 kg and 1.70 m tall performs the ring exercise called "the Christ", in which he keeps his body immobile with his arms extended horizontally as shown in Fig.-Prob.17(a). The angle with the vertical of the cords from which the rings hang is theta = 10. (a) Determine the tension T in the cords holding the rings. (b) Considering each arm of the athlete as a rigid horizontal bar subjected to the forces indicated in Fig.-Prob.17(b), calculate the value of the components RX and RY, the value of the reaction “R” and of the beta angle.- W is the weight of the arm, applied in the middle of its length.- R is the reaction at the shoulder joint O.- RX and RY are the horizontal and vertical components respectively of the reactionapplied at the shoulder joint O.- Note: Consider that the mass of each arm of the athlete is 3% of the total mass, and thatthe length of the arm is equal to 35% of its height. Fig.-Prob.17(a): Man performing the position of "The Christ"Fig.-Prob.17(b):…
Don't copy from other websites solution. The wall crane supports a load of 660lb. The jib ABC has a weight of 152lb and member BD has a weight of 38lb. Each member is uniform and has a center of gtravity at its center. A)Determine the horizontal component of reaction at the pin A. B)Determine the vertical component of reaction at the pin A. C)Determine the horizontal component of reaction at the pin D. D)Determine the vertical component of reaction at the pin D. E)What is the force in the cable at the winch W?
One end of a rod of length L and density ρ is fixed by a frictionless pivot at a depth d under water. Determine the equilibrium positions of the rod in terms of its angle α measured from the vertical, and the investigate whether the equilibrium positions are stable or unstable, given that (a) ρ = 500 kg/m3 ; (b) ρ = 853 kg/m3 (The density of water is ρw = 1000 kg/m3 .)
Determine the magnitude and direction of the angle theta of the force FAB that must be exerted on bar AB to maintain equilibrium of the system. The suspended mass is 110 kg. Neglect the size of the pulley at A and treat all pulleys as smooth. What should happen to maintain the equilibrium of the system if FAB acts with an angle theta= 0°?Consider g = 9.81 m/s2.
A given mass of 23 kg is suspended from a vertical pole by means of a horizontal rod ST hinged at pt.T and a cable SR to the pole; 8m above pt.T. SHOW FBD
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The figure shows the Russel fracture traction device and a mechanical model of the leg. The leg is held in balance in the position indicated by the two weights attached to the two cables. The combined weight of the leg and cast is W=180 N. The distance between the points A and B where the cables are attached to the leg is given as L=100 cm and the angle of the leg with the horizontal is given as γ=8°. Point C is the center of gravity of the cast and leg at three quarters of the L measured from point A (3L/4= 75 cm). The angle that cable 2 makes with the horizontal is measured as β=50°. Accordingly, in order for the leg to remain in balance in the shown position; a) Find the tensile force T1 in cable 1. (Write your result in N)b) Find the tensile force T2 in cable 2. (Write your result in N)c) Find the angle α of cable 1 with the horizontal.
Th lamp , mass = 10 Kg, is suspended in the position shown. The undeformed length of spring AB is 0.84 m and the spring has a stiffness of K = 784 N/m. For L= 2.8 m find Tension in cable AC , Internal force in spring AB, length of AC