2 Power is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power used by the light bulb in Problem 1. B.) Isthis bulb very bright? C.) What is the poucr used bythe light bulb If a 20 v battery Was used instead (Don't forget to recalculate the current)?

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter21: Circuits And Dc Instruments
Section: Chapter Questions
Problem 76PE: Integrated Concepts A 160F capacitor charged to 450 V is discharged through a 31.2-k resistor. (a)...
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Procedure:
The simplest crcuit is a voltage source (i.e. battery) and resistor. The voltage "pushes' the current.
through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage
across a resistor drops. This is called Ohm's Law: V RI.
R
Aww
Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to
one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams
below show these arrangements, the corresponding equivalent resistances, and the main conclusions
of each arrangement.
EQUIVALENT
RESISTANCE
RI
RESISTORS IN
SERIES
V.
R = R, + R, + R,
AWw
Reg
R3
Current is the same throughout the entire circuit. Voltage drops are not the same.
LAB 4 Circuit Analysis
NAME
RESISTORS IN
PARALLEL
V.
R
R2
1.
Rey
R
R R R,
Voltage drops are the same throughout the entire circuit. Current is not the same.
Transcribed Image Text:Procedure: The simplest crcuit is a voltage source (i.e. battery) and resistor. The voltage "pushes' the current. through the circuit. The resistor turns some of the current into heat (or light), and thus, the voltage across a resistor drops. This is called Ohm's Law: V RI. R Aww Circuits can contain several resistors. In circuit analysis, it is convenient to reduce all resistors to one equivalent resistance. Two possible arrangements are called series, and parallel. The diagrams below show these arrangements, the corresponding equivalent resistances, and the main conclusions of each arrangement. EQUIVALENT RESISTANCE RI RESISTORS IN SERIES V. R = R, + R, + R, AWw Reg R3 Current is the same throughout the entire circuit. Voltage drops are not the same. LAB 4 Circuit Analysis NAME RESISTORS IN PARALLEL V. R R2 1. Rey R R R R, Voltage drops are the same throughout the entire circuit. Current is not the same.
1A5 light bulb is connected to a lov battery.
A-) Draw a diagram of the Circuit Indicating
Current flow and v0ltage drops. B.) calculate
the current through the light bulb.
given
hesistance of bulb (R) =5n
Battery voltage (v) =10v
PART Ca)
lov
Vエ
PART (B) Accordin g to Ohm's law
スt こ入
lov
%3D
I=¥ =
current I =
2 Pawer is equal to the voltage times the
Current, P=VI. The unit of power is the Watt,
W.A.) Calculate the power Used oy the light
bulb in Problem 1. B.) Is this bulb very bright?
C.) What is the poucr used bythe light bulb
\f a 20 v battery Was used instead (Dont forget
to recalculate the current)?
3. what is the equivalent resistance of two
102resistars and oe 5-n resistor connected in
H.) scries. B.)what is the Current in the Circuit
If the applicd voltage is 50V c) caculate
Transcribed Image Text:1A5 light bulb is connected to a lov battery. A-) Draw a diagram of the Circuit Indicating Current flow and v0ltage drops. B.) calculate the current through the light bulb. given hesistance of bulb (R) =5n Battery voltage (v) =10v PART Ca) lov Vエ PART (B) Accordin g to Ohm's law スt こ入 lov %3D I=¥ = current I = 2 Pawer is equal to the voltage times the Current, P=VI. The unit of power is the Watt, W.A.) Calculate the power Used oy the light bulb in Problem 1. B.) Is this bulb very bright? C.) What is the poucr used bythe light bulb \f a 20 v battery Was used instead (Dont forget to recalculate the current)? 3. what is the equivalent resistance of two 102resistars and oe 5-n resistor connected in H.) scries. B.)what is the Current in the Circuit If the applicd voltage is 50V c) caculate
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