2 - Rewrite the formula below in CGS units where Q ( m/ sec ), L (m ), and h (m).Q = 3.33 ( L - 0.2 h )(h) 5Where: Q = flow ( ft/ sec )L= crest length ( ft )h = head ( ft )3.33 = constant3 - The frictional pressure drop in the circular pipe under turbulent flow can be calculated using thefollowing formula :0.751.75ΔΡ1,800d1.25Where: AP; = frictional pressure loss ( psi )p = density ( Ib / gal )d = diameter ( in )v= ( ft/ sec )AL = length ( ft)u = viscosity ( cp )1,800 = constant!!Derive the conversion constant to be used in fundamental units ( CGS ).4 - The frictional pressure drop for a Bingham Plastic Model in an annular space uses the formula below:H„Lv1000(d, – d,)² ' 267(d, – d,)Y,LΔΡWhere: APf = psiL = ftdo and d; = inu = cp.v = ft / secY = 1 lbf / 100 ft?Rewrite the formula above in fundamental units (APf = lb/ft?, µ = lbm / ft-sec, L = ft, v = ft/ sec,do and d; = ft, Y, =1 lbf/ ft² ).

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Description: 2 - Rewrite the formula below in CGS units where Q ( m/ sec ), L (m ), and h (m).Q = 3.33 ( L - 0.2 h )(h) 5Where: Q = flow ( ft/ sec )L= crest length ( ft )h = head ( ft )3.33 = constant3 - The frictional pressure drop in the circular pipe under tu

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2 - Rewrite the formula below in CGS units where Q ( m/ sec ), L ( m ), and h ( m ). Q = 3.33 (L - 0.2 h )(h)!5 Where: Q = flow ( ft/ sec ) L= crest length ( ft) h= head ( ft) 3.33 = constant 3 - The frietional pressure drop in the circular pipe under turbulent flow can be calculated using the following formula : ^ALµ025 1,800d125 0.75,1.75 AP, Where: AP;= frictional pressure loss ( psi ) p = density ( Ib / gal ) d = diameter ( in ) v=(ft/sec) AL = length ( ft ) H = viscosity ( cp ) 1,800 = constant Derive the conversion constant to be used in fundamental units ( CGS ). 4 - The frictional pressure drop for a Bingham Plastic Model in an annular space uses the formula below: H„Lv 1000(d, – d,)²' 267(d, – d,) Y,L AP Where: AP= psi L=ft H = cp. v = ft / sec Y = 1 lbf / 100 ft² do and d; = in Rewrite the formula above in fundamental units (APf = Ib/f² , µ = lbm / ft-sec, L = ft, v = ft/ sec, do and d; = ft, Y, = 1 lbf / ft² ).

2 - Rewrite the formula below in CGS units where Q ( m/ sec ), L ( m ), and h ( m ). Q = 3.33 (L - 0.2 h )(h)!5 Where: Q = flow ( ft/ sec ) L= crest length ( ft) h= head ( ft) 3.33 = constant 3 - The frietional pressure drop in the circular pipe under turbulent flow can be calculated using the following formula : ^ALµ025 1,800d125 0.75,1.75 AP, Where: AP;= frictional pressure loss ( psi ) p = density ( Ib / gal ) d = diameter ( in ) v=(ft/sec) AL = length ( ft ) H = viscosity ( cp ) 1,800 = constant Derive the conversion constant to be used in fundamental units ( CGS ). 4 - The frictional pressure drop for a Bingham Plastic Model in an annular space uses the formula below: H„Lv 1000(d, – d,)²' 267(d, – d,) Y,L AP Where: AP= psi L=ft H = cp. v = ft / sec Y = 1 lbf / 100 ft² do and d; = in Rewrite the formula above in fundamental units (APf = Ib/f² , µ = lbm / ft-sec, L = ft, v = ft/ sec, do and d; = ft, Y, = 1 lbf / ft² ).

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter11: Fluid Statics

Section: Chapter Questions

Problem 30PE: (a) Convert normal blood pressure readings of 120 over 80 mm Hg to newtons per meter squared using...

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