2) Run the Java code below and explain why result1/result2 are different and whybefore/after f value are different regarding operand evaluation order.public class GlobalMembers{ public static int b= 4, f= 5;public static int fun1(int a){ a = 17;b=b+2;return a;}public static int fun2(){f=f+1;return f,}public static void main(String args[]){ int a = 6, d= 12, temp;float result1, result2;result1 = (fun1 (a) + b)/ (fun1(a) - d);System.out.print("\n a=" +a +" b="+b+" d=" + d);System.out.print(" result1="+result1);temp = fun1(a);result2 = (temp + b) / (temp - d);System.out.print("\n a=" + a +" b=" +b +" d=" + d);System.out.print(" temp="+ temp +"result2="+ result2);System.out.print("\n before f="+ f);f=f+ fun20;System.out.print("\n after f="+ f);}}

a=6 b=8 d=12result1=4.0 a=6 b=10 d=12result2=5.0 before f=5 after f=11

Answered: 2) Run the Java code below and explain…

2) Run the Java code below and explain why result1/result2 are different and why before/after f value are different regarding operand evaluation order.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter7: User-defined Simple Data Types, Namespaces, And The String Type

Section: Chapter Questions

Problem 1TF

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Concept explainers

Class

Object Oriented Programming System (OOPs) is a programming model built on the perception of “objects” that contains data and methods. The major purpose of Object Oriented Programming is to increase the maintainability and flexibility of programs. Object Oriented Programming gets together data and its behavior (methods) in a single location (object) which makes it easier to understand.

Question

2) Run the Java code below and explain why result1/result2 are different and why
before/after f value are different regarding operand evaluation order.
public class GlobalMembers
{ public static int b= 4, f= 5;
public static int fun1(int a)
{ a = 17;
b=b+2;
return a;
}
public static int fun2()
{f=f+1;
return f,
}
public static void main(String args[])
{ int a = 6, d= 12, temp;
float result1, result2;
result1 = (fun1 (a) + b)/ (fun1(a) - d);
System.out.print("\n a=" +a +" b="+b+" d=" + d);
System.out.print(" result1="+result1);
temp = fun1(a);
result2 = (temp + b) / (temp - d);
System.out.print("\n a=" + a +" b=" +b +" d=" + d);
System.out.print(" temp="+ temp +"result2="+ result2);
System.out.print("\n before f="+ f);
f=f+ fun20;
System.out.print("\n after f="+ f);
}
}

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