2) Use the data you collected in Table 2 to explain the formation of one of the compounds you assembled containing a polyatomic ion. .Ö: Ö: [***] *CaCO3

Q: How many moles of phosphate ions are in 1.00 lb of Ca3(PO4)2 ? 1 lb = 453.59237 g exactly

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Q: Identify the correct structure from the following. A. CH3-C-C-CH3 B. CH3-CH=CH-CH3 C. CH3-CH=CH2 D.…

A: The structures contains carbon-carbo  and carbon- hydrogen bonds . And we know each carbon atoms can…

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Q: h) ОН CH3 [0] ? [0] ?

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A: Given :  Molar Concentration of LiNO3 = 7.5 x 10-5 M  Molar mass of LiNO3 = 69 g/mol

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Q: 8. Consider the cell Fe(s) FeSO.(ag) Hg.SO.(1) Hg() Write the half-cell reactions and the full cell…

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A: Correct option - a Lewis Acid   Boron trifluoride (BH3) is a Lewis acid

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Q: 1. A chem 101 student dissolves 10.6 g of hydrosulfuric acid (H₂S) in 120 mL of water. Calculate the…

A: Mass of H2S = 10.6 g  Volume of water = 120 mL or  = 0.120 L

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Q: * TRANSMITTANCE 100 80 63 20 40- 4000 C5 HID O 3000 3500 liquid between salt plates OTÁZ TTTTTT…

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Q: onsider the titration of 40.0 mL of 0.0600 M C-H5N (a weak base; Kb = 1.70e-09) with 0.100 M HCIO4.…

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Q: synthesis reaction. Please show how to get to the final product show all transition states and…

A: In this question, we will give synthesis steps for this transformation by showing all the…

Q: Chemistry The Solubility Product Constant for iron(II) sulfide is 4.9 x 10-18. Solid potassium…

A: Given :  Ksp of FeS = 4.9 x 10-18  Concentration of Fe(NO3)2 solution = 0.0485 M  Volume of Fe(NO3)2…

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A: To solve this problem we have to use the formula of root mean square velocity.

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Q: 5. Draw the most stable chair conformation of the cyclohexanes below. Also, assign R/S to each…

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Q: Which of the following enols will convert to the ketone on the right upon treatment with acid?

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Q: PLease resolve this solutions!

A: Given,  Mass of Ca3(PO4)2 = 1.00 lb 1 lb = 453.59237 g  Use the formulas :  Number of moles = Given…

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Q: Using standard heats of formation from Appendix C of your text, calculate the standard enthalpy…

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