2. A block is resting on an incline of slope 5:12 as shown in Fig. It is subjected to a force F = 500 N on a slope of 3:4. Determine the components of F parallel and perpendicular to the incline. F = 500 N 3 12

2. A block is resting on an incline of slope 5:12 as shown in Fig. It is subjected to a force F = 500 N on a slope of 3:4. Determine the components of F parallel and perpendicular to the incline. F = 500 N 3 12

Name: YP = 800 N30°30°30°X'2. A block is resting on an incline of slope 5:1
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Description: YP = 800 N30°30°30°X'2. A block is resting on an incline of slope 5:12 as shown in Fig. It issubjected to a force F = 500 N on a slope of 3:4. Determine thecomponents of F parallel and perpendicular to the incline.%3DF = 500 N121

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter12: Static Equilibrium And Elasticity

Section: Chapter Questions

Problem 68P: An aluminium (=2.7g/cm3) wire is suspended from the ceiling and hangs vertically. How long must the...

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