2. A car accelerates uniformly from rest and reaches a speed of 22 m/s in 9.0 s. The diameter of a tire is 50 cm. a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. b) What is the final angular speed of a tire in rev/s?

2. A car accelerates uniformly from rest and reaches a speed of 22 m/s in 9.0 s. The diameter of a tire is 50 cm. a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. b) What is the final angular speed of a tire in rev/s?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter10: Rotation Of A Rigid Object About A Fixed Axis

Section: Chapter Questions

Problem 10.2P: A potters wheel moves uniformly from rest to an angular speed of 1.00 rev/s in 30.0 s. (a) Find its...

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Concept explainers

Angular speed, acceleration and displacement

Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.

Angular Position

Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.

Question

2. A car accelerates uniformly from rest and reaches a speed of 22 m/s in 9.0 s. The diameter of a
tire is 50 cm.
a) Find the number of revolutions the tire makes during this motion, assuming that no
slipping occurs.
b) What is the final angular speed of a tire in rev/s?

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