2. A cut slope is to be made as shown. The unit weight of soil is 18KN/cu.m and the angle of internal friction is 22°. The soil has cohesion of 30 Kpa. The cut slope makes an angle of 30° with the horizontal and the height is 12 m. If the failure plane is 15° from horizontal. Determine a. Frictional force along the failure plane b. Cohesive force along the failure plane Factor of safety against sliding B 24 m A trial failure plane 12 m 30 15° C

2. A cut slope is to be made as shown. The unit weight of soil is 18KN/cu.m and the angle of internal friction is 22°. The soil has cohesion of 30 Kpa. The cut slope makes an angle of 30° with the horizontal and the height is 12 m. If the failure plane is 15° from horizontal. Determine a. Frictional force along the failure plane b. Cohesive force along the failure plane Factor of safety against sliding B 24 m A trial failure plane 12 m 30 15° C

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter13: Slope Stability

Section: Chapter Questions

Problem 13.27CTP

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Similar questions

A 9m cut slope is shown in the figure. The unit weight of soil is 17kN/m3. Friction angle and cohesion along the rock surface are 20 degrees and 24kPa respectively. The slope makes an angle of 300 from horizontal and the failure plane is at 150. Determine the developed frictional force on the failure plane.
A 10m deep slope of 40° is made in a saturated clay of unit weight 20kN/m3. The value of cohesion is given as 72 kN/m2 and the Taylor's stability coefficient is given as 0.18. Compute the factor of safety for the load.
A vertical cut is to be made in a purely cohesive clay deposit (c'=30kPa, φ'=0deg, γ=16kN/m3). Find the maximum height of the cut which can be temporarily supported. From the stability chart, the stability number can be used as 0.261.
Given an infinite slope with the following properties: γ = 17 kN/m3, H = 5 m, β = 34°, φ = 25° and c = 20 kPa. a. Determine the normal stress. b. Determine the shear stress. c. Determine the factor of safety.
A cut slope is to made. The unit weight of soil is 17 kN/m^3 and the angle of internal friction is 20°. The soil has a cohesion of 24 kPa. The cut slope makes an angle of 30° with the horizontal and the height is 9 m. if the trial failure plane is 15°from the horizontal. Determine the following: 1. Frictional force along the failure plane. 2. Cohesive force along the failure plane. 3. Factor of safety against sliding.
A cut slope of h= 7m was excavated in a saturated clay with a slope of angle beta = 45 degrees with the horizontal. The Previous explorations showed that a rock layer was located at a depth of 14 m. Given that, c = 60 kN/m² and unit weight = 17 kN / (m ^ 3) . Determine the factor of safety.
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What is the factor of safety of a slope behind a geomembrane-lined pond when it is empty if the soil fails under undrained conditions? The slope is 3H to 1V, 7.5-meters deep, and will be of the toe failure type (i.e., n = 1.0). The soil’s unconfined compressive strength is qu = 35 kN/m2 (note that qu = 2c) and its unit weight is 18 kN/m3. Show your work! **HINT: you will need to reference the figure below for your Ns value for “soils whose strength can be approximated by undrained conditions”.
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