2. A parallel plate capacitor is filled with Bakelite (from Table 4-2, ɛ, = 5 ). The plate spacing is d = 1 mm and plate area A = 0.01 m?. (a) What is the capacitance? (Neglect fringing.) (b) What is the stored energy if 10 kV is applied?
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- A capacitor uses air as a dielectric and has a capacitance of 3 F. A dielectric material is inserted between the plates without changing the spacing, and the capacitance becomes 15 F. What is the dielectric constant of this material?You are working in an industrial plant. You have been instructed to double the capacitance connected to a machine. The markings on the capacitor, however, are not visible. The capacitor is connected to 560 volts and an ammeter indicates a current of 6 amperes flowing to the capacitor. What size capacitor should be connected in parallel with the existing capacitor? What is the minimum AC voltage rating of the new capacitor? What is the minimum DC voltage rating of the new capacitor? What is the minimum KVAR size that can be used in this installation?A pure capacitive circuit is connected to a 480-volt, 60-Hz power source. An ammeter indicates a current flow of 24 amperes. The circuit current must be reduced to 16 amperes by connecting a second capacitor in series with the first. What is the value of the existing capacitor? What value capacitor should be connected in series with the original capacitor to limit the circuit current to 16 amperes?
- You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.4. In what form is the energy of a capacitor stored?Fill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5
- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.Two parallel-plate capacitors are constructed using dielectric materials with dielectric constants κ1 = 3 and κ2 = 5, as shown in Figure. Parallel-plates have the area A = 0.7 m2 . The distance is d = 0.05 m. A potential difference of ∆V = 24 ? is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential ΔV1 . (ε0=8.85×10-12 C2 /N×m2 )A parallel plate capacitor with 26 interleaved parallel plates having area of cross section,300mm*500mm and plates are separated by 0.030mm using rubber with dielectric constant 8.5.i. Estimate capacitance and charge stored in the capacitor when a voltage, 250V is applied. [3]ii. What are the modifications required to double the charge storing capacity of given capacitorwithout changing the applied voltage? Justify your answer.
- A capacitor has a disk-shaped dielectric of ceramic (εr = 7500) that has a 0.15 cm diameter and 0.975 mm thick. The disk insulator is parallel-coated on both sides with silver, these coating being plates. Find the capacitance, in nF, of the material.A resistor and a capacitor are connected in series with a variable inductor. When the circuit is connected to a 240 – V, 50 – Hz supply, the maximum current given by varying the inductance is 0.5 A. At this current, the voltage across the capacitor is 250 V. Calculate the values of (a) the resistance, (b) the capacitance, and (c) the inductance. draw circuit diagramThe upper part of the circuit shown on the figure below consists of two parallel wires A (bluewire) and B (red wire), with following properties: Wire A: length l, resistivity ρA, cross section area SA.Wire B: length l, resistivity ρB, cross section area SB.The resistivity of the remaining (black) wires is negligible.On the right part of the circuit there is a capacitor: half of the capacitoris filled with twodielectric blocks with equal volume with dielectric constants κ1 and κ2. The other half isvacuum. The area of the capacitor plates is SC.(a) Find the equivalent RC circuit of the circuit. Deduce the time constant.(b) How much energy is stored in the capacitor in steady state?