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2. Calculate the mass defect, nuclear binding energy (in J) and the binding energy per nucleon of the following isotopes; a) “He Z = 2, (4.0026amu) and b) 184W Z = 74, (183.9510 amu). %3D 3. In the thorium decay series, thorium-232 loses a total of 6 alpha particles and 4 beta particles in a 10-stage process. What is the final isotope produced?

2. Calculate the mass defect, nuclear binding energy (in J) and the binding energy per nucleon of the following isotopes; a) “He Z = 2, (4.0026amu) and b) 184W Z = 74, (183.9510 amu). %3D 3. In the thorium decay series, thorium-232 loses a total of 6 alpha particles and 4 beta particles in a 10-stage process. What is the final isotope produced?

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter18: Nuclear Chemistry
Section: Chapter Questions
Problem 27QRT
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C. Answer the following 2. Calculate the mass defect, nuclear binding energy (in J) and the binding energy per nucleon of the following isotopes; a) “He Z= 2, (4.0026amu) and b) 184W Z = 74, (183.9510 amu). 3. In the thorium decay series, thorium-232 loses a total of 6 alpha particles and 4 beta particles in a 10-stage process. What is the final isotope produced?
Transcribed Image Text:C. Answer the following 2. Calculate the mass defect, nuclear binding energy (in J) and the binding energy per nucleon of the following isotopes; a) “He Z= 2, (4.0026amu) and b) 184W Z = 74, (183.9510 amu). 3. In the thorium decay series, thorium-232 loses a total of 6 alpha particles and 4 beta particles in a 10-stage process. What is the final isotope produced?
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