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2. Calculate the theoretical yield of potassium alum from 1.0000 g of aluminum, assuming that the aluminum is the limiting reagent. First, write the net reaction by adding the net ionic g equations that represent the four steps in the synthesis: 2 Al +2 OH + 6 HOH → 2 Al(OH)4¯ + 3 H2 2 Al(OH)4 + 2 H* → 2 Al(OH)3 +2 HOH 2 Al(OH)3 + 6 H* → 2 Al³* + 6 HOH 2 K* + 2 Al* + 4 SO42 + 24 HOH → 2 KAI(SO4)2 12 H20

2. Calculate the theoretical yield of potassium alum from 1.0000 g of aluminum, assuming that the aluminum is the limiting reagent. First, write the net reaction by adding the net ionic g equations that represent the four steps in the synthesis: 2 Al +2 OH + 6 HOH → 2 Al(OH)4¯ + 3 H2 2 Al(OH)4 + 2 H* → 2 Al(OH)3 +2 HOH 2 Al(OH)3 + 6 H* → 2 Al³* + 6 HOH 2 K* + 2 Al* + 4 SO42 + 24 HOH → 2 KAI(SO4)2 12 H20

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter19: Transition Metals And Coordination Chemistry
Section: Chapter Questions
Problem 14E: A 2.5624-g sample of a pure solid alkali metal chloride is dissolved in water and treated with...
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2. Calculate the theoretical yield of potassium alum from 1.0000 g of aluminum, assuming that the aluminum is the limiting reagent. First, write the net reaction by adding the net ionic 1. Bring a prefer. (There's more people to share.) equations that represent the four steps in the synthesis: 2 Al +2 OH + 6 HOH → 2 Al(OH)4¯ + 3 H2 2 Al(OH)4+2 H* →2 Al(OH)3 +2 HOH 2 Al(OH)3 + 6 H* → 2 Al³+ + 6 HOH 2 K* + 2 Al3+ + 4 SO2- + 24 HOH →2 KAI(SO4)2·12 H20 shot on moto g' power Crystal H.
Transcribed Image Text:2. Calculate the theoretical yield of potassium alum from 1.0000 g of aluminum, assuming that the aluminum is the limiting reagent. First, write the net reaction by adding the net ionic 1. Bring a prefer. (There's more people to share.) equations that represent the four steps in the synthesis: 2 Al +2 OH + 6 HOH → 2 Al(OH)4¯ + 3 H2 2 Al(OH)4+2 H* →2 Al(OH)3 +2 HOH 2 Al(OH)3 + 6 H* → 2 Al³+ + 6 HOH 2 K* + 2 Al3+ + 4 SO2- + 24 HOH →2 KAI(SO4)2·12 H20 shot on moto g' power Crystal H.
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