2. Evaluate 2y"+3y'-2y=te-2t ,y(0)=0, y'(0)=-2 1 y(0) 125 A) y(1) 25 (96e2+96e-2-10te-2-2²-2) -2t (-96e Option 1 O Option 2 y(t)(-96e -2t +96e-2t+10te 2tt²e-²) 25 Option 3 -2t+-10te-2t 25t²e-2t) +96e

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