2. Lim Z2-1 / Z2+3Z-1

Q: 3x2 + 1?y? + 3y? + 3z2 3 Show that lim (1,y,2)+(0,0,0) 1² + y? + z²

A: The given rational function is 3x2+x2y2+3y2+3z2x2+y2+z2. Evaluate the limit along the line y=0,z=0.…

Q: 2 _9 ii)lim- t-3 t2+4

A: Given query is to find the limit of the expression.

Q: Find the limits

A:

Q: Vh? + 15 – Vh + 15 Vh + 3 – 2 - (b) lim h→1 Answer: 1/2 -

A: L' Hospital Rule :If we have indeterminate form of the type 00 or±∞±∞ ,Then…

Q: I+3 lim z-3 + x- 6

A:

Q: 3.) lim r/z2

A: let t=x1x2ln(t)=1x2ln(x)t=e1x2ln(x)in the question it is asked to find the limit of t when x tends…

Q: 3) lim (x - 1)-¹ Inx x→1

A: Our Aim is to evaluate the limit of the expression given below:-limx→1x-1-1 ln (x) -(i)

Q: lim,-2[x + 1] – [x] = %3D

A: Here [*] denotes the greatest integer function. Use the property of greatest integer function, [x +…

Q: find L1=lim 23+i !-2 !+2

A: Topic:- calculus

Q: iz?-z- lim- z2-1 %3D i0 -i O 00

A:

Q: Part I x2-9 1. lim х>з х-3 -2. 2. lim х2+5х-6 X→1 х2—1 2x2-х-21 3. lim X→-3 9-х2

A: Note: students has mentioned only 3 question no so I solved accordingly

Q: sin(Va-4) lim -16 16(-1)

A: For any real value of b, the expression, limx→bx is defined aslimx→bx =b . If limx→bf(x)g(x) takes…

Q: 4.7 Show that does not exist. lim (x-2)(y-1) (x, y) → (2, 1)(x - 2)² + (y − 1)² -

A: In this question we have to show that limit does not exist.

Q: 5. Evaluate lim x→2 x² - 16 X x-2

A: According to Bartelby's guidelines, we can only solve one question at a time, please post again to…

Q: 3*-7* x-0 2-15x d. lim

A:

Q: c. lim (1-x) tan

A:

Q: d. lim f(x) e. f(0) f. f(-1)

A: (d) From the graph it is clear as x approaches 0 from left side , f(x) approaches -∞ as the curve…

Q: Va²+9-5 Evaluate lim > 4 %3D x+4

A:

Q: (a) 5x-3 – 4 (i) Lim: X--0 2x-2 +9 (x- 3)2 (ii) Lim 7- 2x – 3

A:

Q: 2n2+3п-4 Find lim,→∞ . (show all necessary details) 3"

A: limit value = ?

Q: tan( xy) lim = ? 2. (х.у) -> (0,1) х*у+х (c) (с) 3 (d) - (е) 1 (а) 0 (b)

A: Limit is the value of the expression as the independent variable approaches certain value, not…

Q: Q2) A) 1-VI+1 sinax 3) lim I+1 1) lim 2) lim

A: Given that:                       (1)limx→∞x+1x2+3 (2)limx→01-x+1x(3)limx→0sin3xx   NOTE: As per our…

Q: lim x-+∞ [5x+2]] X

A:

Q: Find the following 1 I – 6 (a) lim I4- 4 -I (b) lim -3 27 - r (c) lim -6 (x – 6)6

A:

Q: 1 + x² – 4x + 3 lim T→1- T2 – x

A:

Q: z -1- i 2→1+i \ 22 – 2z + 2, 4. Find lim 2.

A:

Q: 1-x 6. lim X-3 X+3

A:

Q: 5x-3 – 4 | (i) Lim x-0 2x-2 +9 (x – 3)2 (ii) Lim X00 x2 2х — 3 2

A:

Q: sec 2x Q3. Find the lim,0 3x csc2x

A:

Q: aterminate form, use factor 2-1 1. lim X14x+4 +2x-15 2. lim I-3 x+4x-21 x+x-20 3. lim X-4 r-64

A:

Q: y? lim (х.у)-(1,0) х2 + у? — 2х + 1

A:

Q: 4. lim x² +2x+5) X-2

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: Determine the value of 6>0 for which lim (3x -1)=47 X4 A 6 = max{-4-16 -, -4+, 16 + | 3 6 =…

A: Given: limx→43x2-1=47 and δ>0

Q: g expressions a. lim (2z - 1)(2-1)

A: Given : apply chain rule    find limit of about separately

Q: lim (sec³ x – tan x) 3 X-

A: Given : limx→π2(sec3x−tan3x)

Q: 2x - 4 lim (Simplify your answer.) Vox? + 2 II

A:

Q: Can you please answer this question and show all of the steps and say the correct letter

A: Given limit

Q: 28. 16(V1+x -1) lim

A: Topic = Limits

Q: x²y + x³y² lim (x,y)-(-2,1) x² + y2

A:

Q: raleuto lim Y-12 XB

A: First rationalize the expression as follows.

Q: 2x2-ху-у? x²-y² Evaluate lim (х.у) - (1,1) (2) 3. 2

A:

Q: t2 – 1 2. lim t-2 t² + 3t – 1

A: Evaluate: limt→-2t2-1t2+3t-1 Substitute t=-2 . limt→-2t2-1t2+3t-1=-22-1-22+3-2-1

Q: tan(ху) = ? .2. (х,у) >(0,1) х*y+x lim

A:

Q: 1 1 lim (х ,у)->(2,-3) X y

A:

Q: x²-9 lim is equal to: х->3 х-3 а) 2 b) 3 с) 6

A: It's very easy!!! see in next step

Q: 3i - lim t-25 (t – 20)2

A: We substitute t=25 in the given expression

Q: neither x² – 9 A) limx→3 4х — 12 - x2 – 1 - B) limx→1 VI – 1

A:

Q: 4. lim (6x – 3) 5. lim 6. lim 7. lim 8. lim r-1 2-16 9. lim 10. lim(5x - 3x+ 7x + 2)5

A: B)4)limx→-2(6x-3)=6(-2)-3limx→-2(6x-3)=-12-3limx→-2(6x-3)=-15.5)limx→13(x+2)(x+3)=(13+2)(13+3)limx→1…

Q: sec (2)7** b) lim ес x→+

A: We have to find limit

Q: Evaluate x² –1 lim,→1 -1

A: We know that formula , a2 - b2 = ( a + b ) ( a - b ) Now x2 - 1 = x2 - 12 = ( x + 1) ( x - 1)

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.