I only need question 2 answered. Question 1’s are only there for reference. Use the data below to answer questions #1-4.Person idMother'sRespondent'seducation(X- Mean) * (Y-Мean)2.9 * 2.6 = 7.54X- MeanY- Mean(X-Mean)?(Y-Mean)?2#education1161616 - 13.1 = 2.916 - 13.4 = 2.62.92 = 8.412.62 = 6.762161816 - 13.1 = 2.918 - 13.4 = 4.62.9 * 4.6 = 13.342.92 = 8.414.62 = 21.1631214(-1.1) * 0.6 = -0.66(-1.1) * 0.6 = -0.66(-4.1) * (-4.4) = 18.04(-5.1) * (-5.6) = 28.565.9 * (-1.4) = -8.260.9 * 6.6 = 5.94(-0.1) * (-0.4) = 0.04(-1.1) * (-1.4) = 1.5412 - 13.1 = -1.114 - 13.4 = 0.6(-1.1)? = 1.21(-1.1)? = 1.21(-4.1)2 = 16.810.62 = 0.364121412 -13.1 = -1.114 - 13.4 = 0.60.62 = 0.36(-4.4)2 = 19.36(-5.1)2 = 26.01 (-5.6)² = 31.36(-1.4)2 = 1.966.62 = 43.56(-0.4)2 = 0.16(-1.4)² = 1.96599-13.1 = -4.19- 13.4 = -4.48.8.8- 13.1 = -5.18- 13.4 = -5.67191219 - 13.1 = 5.912 - 13.4 = -1.45.92 = 34.818142014 - 13.1 = 0.90.92 = 0.81(-0.1)2 = 0.01(-1.1)² = 1.2120 - 13.4 = 6.6131113 - 13.1 = -0.113 - 13.4 = -0.410121212 - 13.1 = -1.112-13.4 = -1.413.113.46.5429.8912.71. Calculate Pearson's r. Write one or two sentences describing the results (Is there anassociation? Is it positive or negative? Is it weak, moderate or strong?)E(XX)(Y – Y)|V[E(X - X)²][2(Y – Y)*]6.542r =V9.89 x 12.70.584There is a moderate positive association between how many years of education the respondentshad when compared to their mothers. Those with well-educated mothers are likely to be well-educated themselves.2. Suppose this is a random sample. Test the hypothesis that there is an associationbetween mother's and respondent's education in the population. Use a = 0.05.

Question

Accepted Answer

Given:

Mother's education, X
Respondent's education, Y

16
16

16
18

12
14

9
9

8…

2. Suppose this is a random sample. Test the hypothesis that there is an association between mother's and respondent's education in the population, Use a = 0.05.