2. SWIMMER'S FLEXIBILITY STUDY Some statistics Before: mean = 19.4160; median = 18.46 After: mean = 18.8433; median = 18.86 Let difference = before – after d = 0.5727 ma = 0.95 Wilk-Shapiro Test for Normality data: data: before after data: difference W = 0.92695 W = 0.97168 p-value = 0.8821 W = 0.96992 p-value = 0.8569 p-value 0.2456 Student's t-test on Paired Samples: Before vs After Ha: less than 0 Ha: not equal to 0 t = 1.7819 p-value = 0.09646 Ha: greater than 0 t = 1.7819 p-value = 0.04823 t = 1.7819 p-value = 0.9518 Ha: not equal to 0 V = 89.5 p-value = 0.09947 Wilcoxon Matched-Pairs Signed Ranks Test: Before vs After Ha: less than 0 V = 89.5 p-value = 0.9558 Ha: greater than 0 V = 89.5 p-value = 0.04974 F-test for Equality of Variances F = 1.1255 p-value = 0.828 Ha: not equal to 0 t = 0.58311 p-value = 0.5645 Student's t-test on Two Independent Pop’n Means: Before vs After Ha: greater than 0 t = 0.58311 Ha: less than 0 t = 0.58311 p-value = 0.7178 p-value = 0.2822 Welch's t-test on Two Independent Pop’n Means: Before vs After Ha: not equal to 0 t = 0.58311 p-value = 0.5645 Ha: greater than 0 t = 0.58311 p-value = 0.2823 Ha: less than 0 t = 0.58311 p-value = 0.7177 Mann-Whitney Test on Two Independent Pop’n Means: Before vs After Ha: not equal to 0 Ha: greater than 0 W = 120 p-value = 0.3874 Ha: less than 0 W = 120 p-value = 0.7748 W = 120 p-value = 0.6281

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 10CYU
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Question
Answer letters b, c and d. Use image two as to determine the p value and point estimate
2. SWIMMER'S FLEXIBILITY STUDY
Some statistics
Before:
mean = 19.4160; median = 18.46
After:
mean = 18.8433; median = 18.86
Let difference = before – after
d = 0.5727
md = 0.95
Wilk-Shapiro Test for Normality
data:
before
data:
after
data:
difference
W = 0.96992
W = 0.92695
p-value = 0.2456
W = 0.97168
p-value = 0.8821
p-value = 0.8569
Ha: not equal to 0
t = 1.7819
p-value
Student's t-test on Paired Samples: Before vs After
Ha: less than 0
t = 1.7819
Ha: greater than 0
t = 1.7819
p-value = 0.04823
= 0.09646
p-value = 0.9518
Ha: not equal to 0
V = 89.5
p-value = 0.09947
Wilcoxon Matched-Pairs Signed Ranks Test: Before vs After
Ha: less than 0
V = 89.5
p-value = 0.9558
Ha: greater than 0
V = 89.5
p-value = 0.04974
F-test for Equality of Variances
F = 1.1255
p-value
= 0.828
Student's t-test on Two Independent Pop'n Means: Before vs After
Ha: not equal to 0
t = 0.58311
p-value = 0.5645
Ha: less than 0
t = 0.58311
p-value = 0.7178
Ha: greater than 0
t = 0.58311
p-value = 0.2822
Ha: not equal to 0
t = 0.58311
p-value = 0.5645
Welch's t-test on Two Independent Pop'n Means: Before vs After
Ha: less than 0
t = 0.58311
Ha: greater than 0
t = 0.58311
p-value = 0.7177
p-value = 0.2823
Ha: not equal to 0
W = 120
p-value = 0.7748
Mann-Whitney Test on Two Independent Pop'n Means: Before vs After
Ha: less than 0
W = 120
Ha: greater than 0
W = 120
p-value = 0.6281
p-value = 0.3874
Transcribed Image Text:2. SWIMMER'S FLEXIBILITY STUDY Some statistics Before: mean = 19.4160; median = 18.46 After: mean = 18.8433; median = 18.86 Let difference = before – after d = 0.5727 md = 0.95 Wilk-Shapiro Test for Normality data: before data: after data: difference W = 0.96992 W = 0.92695 p-value = 0.2456 W = 0.97168 p-value = 0.8821 p-value = 0.8569 Ha: not equal to 0 t = 1.7819 p-value Student's t-test on Paired Samples: Before vs After Ha: less than 0 t = 1.7819 Ha: greater than 0 t = 1.7819 p-value = 0.04823 = 0.09646 p-value = 0.9518 Ha: not equal to 0 V = 89.5 p-value = 0.09947 Wilcoxon Matched-Pairs Signed Ranks Test: Before vs After Ha: less than 0 V = 89.5 p-value = 0.9558 Ha: greater than 0 V = 89.5 p-value = 0.04974 F-test for Equality of Variances F = 1.1255 p-value = 0.828 Student's t-test on Two Independent Pop'n Means: Before vs After Ha: not equal to 0 t = 0.58311 p-value = 0.5645 Ha: less than 0 t = 0.58311 p-value = 0.7178 Ha: greater than 0 t = 0.58311 p-value = 0.2822 Ha: not equal to 0 t = 0.58311 p-value = 0.5645 Welch's t-test on Two Independent Pop'n Means: Before vs After Ha: less than 0 t = 0.58311 Ha: greater than 0 t = 0.58311 p-value = 0.7177 p-value = 0.2823 Ha: not equal to 0 W = 120 p-value = 0.7748 Mann-Whitney Test on Two Independent Pop'n Means: Before vs After Ha: less than 0 W = 120 Ha: greater than 0 W = 120 p-value = 0.6281 p-value = 0.3874
2. SWIMMER'S FLEXIBILITY STUDY
Swimming requires complete body movement as defined in sports science. A swimmer's
flexibility helps in his/her movement in water, thus making him/her a faster swimmer. In a
study conducted to determine if there is an improvement in swim speed after doing
flexibility exercise, 15 swimmers of the same characteristics were randomly selected. They
were asked to do a 25-m freestyle and their swim speed (in seconds) were recorded. After
this, a flexibility exercise was done. All'the swimmers were then asked to do another 25-
m freestyle and their swim speed (in seconds) were also recorded.".
(Use before after in your computations)
Swimmer
4
7
8
Before
16.87
19.42
20.04
22.82
24.24
17.76
23.91
17.17
After
15.82
18.47
20.43
21.76
23.88
18.12
20.96
16.03
Swimmer
10
11
12
13
14
15
Before
17.45
15.53
22.15
18.26
16.65
20.51
18.46
After
18.48
15.41
20.91
19.18
14.45
18.86
19.89
a. The samples above are related (self-pair) (related/independent) samples.
b. At 5% alpha, perform test(s) to determine which test procedure should be used
to compare the two populations involved. For EACH test, indicate the following:
Ho (in words):
Ha (in words):
Test Procedure:
follows normal distribution
does not follow normal distribution
p-value:
Conclusion:
c. Based on the results in #2b, the appropriate test procedure to answer the
objective of the researchers is a
test procedure.
(parametric/non-parametric)
d. A point estimate of the average difference in swim speed of swimmers before
and after doing flexibility exercise is
Transcribed Image Text:2. SWIMMER'S FLEXIBILITY STUDY Swimming requires complete body movement as defined in sports science. A swimmer's flexibility helps in his/her movement in water, thus making him/her a faster swimmer. In a study conducted to determine if there is an improvement in swim speed after doing flexibility exercise, 15 swimmers of the same characteristics were randomly selected. They were asked to do a 25-m freestyle and their swim speed (in seconds) were recorded. After this, a flexibility exercise was done. All'the swimmers were then asked to do another 25- m freestyle and their swim speed (in seconds) were also recorded.". (Use before after in your computations) Swimmer 4 7 8 Before 16.87 19.42 20.04 22.82 24.24 17.76 23.91 17.17 After 15.82 18.47 20.43 21.76 23.88 18.12 20.96 16.03 Swimmer 10 11 12 13 14 15 Before 17.45 15.53 22.15 18.26 16.65 20.51 18.46 After 18.48 15.41 20.91 19.18 14.45 18.86 19.89 a. The samples above are related (self-pair) (related/independent) samples. b. At 5% alpha, perform test(s) to determine which test procedure should be used to compare the two populations involved. For EACH test, indicate the following: Ho (in words): Ha (in words): Test Procedure: follows normal distribution does not follow normal distribution p-value: Conclusion: c. Based on the results in #2b, the appropriate test procedure to answer the objective of the researchers is a test procedure. (parametric/non-parametric) d. A point estimate of the average difference in swim speed of swimmers before and after doing flexibility exercise is
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