3. What concepts or properties do you need to solve the problems? B. Read the given article/texts carefully. Then, complete the table and answer the questions that follow,EssentialText 1Text 2Text 3QuestionThe computer terminals in aschool are labeled 1 to 300,The technician wants toknow if the computers are ingood working condition bytesting 50 of these units. Herandomly selects the 12th tobe the first unit to be tested.Which computer unit will betested next?Fifty people were surveyedThe table shows theon the number of full-length frequency count of theemployees' responses to thesurvey of employees'satisfaction level. Anumerical rating of 5 isassigned to very satisfied(VS), 4 to satisfied (S), 3 toneutral (N), 2 to somewhatdissatisfied (SD), and 1 tovery dissatisfied (VD).Number ofEmployces2520movies watched in a year.Number ofРегsonsNumber ofMoviesWatched19-2116-18113-155710-127-984-60-3At least how many moviesshould one watch to belongto upper 5th percentile?1215Level ofSatisfactionVS (5)S (4)N (3)SD (2)VD (1)What is the employees' Levelof Satisfaction with the1343How canissues andcompany? And at whatpercent?Answer:problems onyourrespectivecommunitybe solved?Answer:Answer:Ore should wotch at legst 1625 or 17 movies to belog to The employees Level of Satisfaction with the company is The computer unit will be tested next is the 18th comouterthe upper 5th percentile.3,92 or aprox, (Satisfied) with 78,4% satisfaction rate,Supporting Texts:Supporting Texts:Supporting Texts:A person should wateh at least 17 movies to belong to theBased on the aample groupad data of 65 amployeea, theThe computer termnale in a school are labeled 1 to 300.mean is 3.92 or approximately 4 which indioate asupper Sth percentile or the 95th percentile. This is beoause Sutiefied (S) on the level of sutiefootion This le because I The techrikian wants to teet 50 urita and rardomly selectawe used the formula Pru bpo +In*t/100 - of /fpe 1ieome up to my own eomputation and formula which lawhere bpen first olass boundary in the loated cumulative weighted means VS(25) + K(20) + NC13) + SDC4) +VD) / total number of employees where VS= veryatiafind, S- autiufied, N- rentral, SD- whut12h to be the first unit to be tested, The second or thenext computer urit will be tested is the 18th unit, This isfrequeney, ne value we need to find, fe frequeney of thevalue (total number of persons), and of oumulativebecause we use my buit up 2 formala which is umbereof planned to test computer units total computer termhakdissatisfied, VD= very dissatisfied. the mean is 3.92 orapproximately 4 which indicate as Saliefied (S) en thelevel of sutisfuction, and total number of employeas 65,frequeney of the closs before the class with the value ofn schools" and "first unit to be tested + anawer for thethe given perentile.first formula".Reason:Reason:First, we get the the cumalative frequency and classReason:To determine the level of satisfaction, we simply get theFor this problem, we use my buit up 2 formulas andbourdaries to oomplete the table, now we lve for themean by getting the sum of multiplied frequency to itapercentile. So we reed to colesiate the 95th percentile. We numerical value and divided it by the total frequency formthe formula "weighted mean= VS(25) + S(20) + NC13) +upper Sth percentile, Upper Sth percentile is 100-5-95thaubstitute the values needed, There are 300 oomputerterminale in a school Fifty units are needed to test if theuoe the formula "Pr Ibpo +Entf/100 - ef fpa 11", Wecomputers are in good working condition, Since the first unitto be tested is 12th, we need to divide firet the number ofeumulative frequeney volue greater or equal to 47.5. After substitute the given vales to the formua, weghted meane eomputer terminals which is 300 to the numbers of unitsfirst find the n*T/100. 95*50 (50 ie from the total numberSD(4) + VD(1) / total number of employees". Weof persons)a 4,750/100- 47.5. Then we loeate thedutermiring, we firnd the n-95, bde-15.5, et-47, fpe-2,5(25) + 4(20) + 3(13) + 2(4) + 1(1) / 65 then we get theneeded to test which is 50, It is equal to 6 as the intervolof testing, atter that we use the first unit to be testedand i=18.5-15.5-3. We subetitute the values in the formulaanswer of 3.92 and if we round it off, we'l get the anawerthen inturprut, P95- 15.5 (47,5- 47/ 2) 3, and theanswer is 16.25. Se vakue is 16.25 is in the upper 5th-of 4 that shows the employees' level of satisfaction ofwhich is 12 to be added to the interval of testing and thepercentile or the 95th percentile round 16,25 up te thenearest whole number is 17 Tie io because we oon't haveSatisfind, And to determine the level of satisfaction inpercent, we divided the mean to the highest value of levelsum is 18 which will be the next computer unit to be tested.decimcal valu tor number of movina xit is a disernievartable). So we must have at least 17 movles to watch to of satisfaction and multiply it by 100 then we get thehelong tn the pper fith pereonrililn.anawer of 78,4%Common Ideas in Reasons:It is important to note that the observation are collected randomly, hence,there is no given biased/preference for one observation over another It's worth noting that the observations are gathered at random, so there's noprejudice or biased for one observation over another.Enduring Understanding/Generalization:Frequeny couts, grouped data, serve as pood starting of desripitivestatistically analysis given a data set it gives more structured/ compactanalysis and it easinr /mure convenient to use as compared to ungroupeddata When oppused to ungroaped tlata, fruuency cuurta, BrOuped data, Jervedas a uselul beginning point for deseriptive statiratically analysis given a datahet. It provideu a more structured/ condensed analysin and is uusier/more

Question

3. What concepts or properties do you need to solve the problems? B. Read the given article/texts carefully. Then, complete the table and answer the questions that follow,EssentialText 1Text 2Text 3QuestionThe computer terminals in aschool are labeled 1 to 300,The technician wants toknow if the computers are ingood working condition bytesting 50 of these units. Herandomly selects the 12th tobe the first unit to be tested.Which computer unit will betested next?Fifty people were surveyedThe table shows theon the number of full-length frequency count of theemployees' responses to thesurvey of employees'satisfaction level. Anumerical rating of 5 isassigned to very satisfied(VS), 4 to satisfied (S), 3 toneutral (N), 2 to somewhatdissatisfied (SD), and 1 tovery dissatisfied (VD).Number ofEmployces2520movies watched in a year.Number ofРегsonsNumber ofMoviesWatched19-2116-18113-155710-127-984-60-3At least how many moviesshould one watch to belongto upper 5th percentile?1215Level ofSatisfactionVS (5)S (4)N (3)SD (2)VD (1)What is the employees' Levelof Satisfaction with the1343How canissues andcompany? And at whatpercent?Answer:problems onyourrespectivecommunitybe solved?Answer:Answer:Ore should wotch at legst 1625 or 17 movies to belog to The employees Level of Satisfaction with the company is The computer unit will be tested next is the 18th comouterthe upper 5th percentile.3,92 or aprox, (Satisfied) with 78,4% satisfaction rate,Supporting Texts:Supporting Texts:Supporting Texts:A person should wateh at least 17 movies to belong to theBased on the aample groupad data of 65 amployeea, theThe computer termnale in a school are labeled 1 to 300.mean is 3.92 or approximately 4 which indioate asupper Sth percentile or the 95th percentile. This is beoause Sutiefied (S) on the level of sutiefootion This le because I The techrikian wants to teet 50 urita and rardomly selectawe used the formula Pru bpo +In*t/100 - of /fpe 1ieome up to my own eomputation and formula which lawhere bpen first olass boundary in the loated cumulative weighted means VS(25) + K(20) + NC13) + SDC4) +VD) / total number of employees where VS= veryatiafind, S- autiufied, N- rentral, SD- whut12h to be the first unit to be tested, The second or thenext computer urit will be tested is the 18th unit, This isfrequeney, ne value we need to find, fe frequeney of thevalue (total number of persons), and of oumulativebecause we use my buit up 2 formala which is umbereof planned to test computer units total computer termhakdissatisfied, VD= very dissatisfied. the mean is 3.92 orapproximately 4 which indicate as Saliefied (S) en thelevel of sutisfuction, and total number of employeas 65,frequeney of the closs before the class with the value ofn schools&#34; and &#34;first unit to be tested + anawer for thethe given perentile.first formula&#34;.Reason:Reason:First, we get the the cumalative frequency and classReason:To determine the level of satisfaction, we simply get theFor this problem, we use my buit up 2 formulas andbourdaries to oomplete the table, now we lve for themean by getting the sum of multiplied frequency to itapercentile. So we reed to colesiate the 95th percentile. We numerical value and divided it by the total frequency formthe formula &#34;weighted mean= VS(25) + S(20) + NC13) +upper Sth percentile, Upper Sth percentile is 100-5-95thaubstitute the values needed, There are 300 oomputerterminale in a school Fifty units are needed to test if theuoe the formula &#34;Pr Ibpo +Entf/100 - ef fpa 11&#34;, Wecomputers are in good working condition, Since the first unitto be tested is 12th, we need to divide firet the number ofeumulative frequeney volue greater or equal to 47.5. After substitute the given vales to the formua, weghted meane eomputer terminals which is 300 to the numbers of unitsfirst find the n*T/100. 95*50 (50 ie from the total numberSD(4) + VD(1) / total number of employees&#34;. Weof persons)a 4,750/100- 47.5. Then we loeate thedutermiring, we firnd the n-95, bde-15.5, et-47, fpe-2,5(25) + 4(20) + 3(13) + 2(4) + 1(1) / 65 then we get theneeded to test which is 50, It is equal to 6 as the intervolof testing, atter that we use the first unit to be testedand i=18.5-15.5-3. We subetitute the values in the formulaanswer of 3.92 and if we round it off, we'l get the anawerthen inturprut, P95- 15.5 (47,5- 47/ 2) 3, and theanswer is 16.25. Se vakue is 16.25 is in the upper 5th-of 4 that shows the employees' level of satisfaction ofwhich is 12 to be added to the interval of testing and thepercentile or the 95th percentile round 16,25 up te thenearest whole number is 17 Tie io because we oon't haveSatisfind, And to determine the level of satisfaction inpercent, we divided the mean to the highest value of levelsum is 18 which will be the next computer unit to be tested.decimcal valu tor number of movina xit is a disernievartable). So we must have at least 17 movles to watch to of satisfaction and multiply it by 100 then we get thehelong tn the pper fith pereonrililn.anawer of 78,4%Common Ideas in Reasons:It is important to note that the observation are collected randomly, hence,there is no given biased/preference for one observation over another> It's worth noting that the observations are gathered at random, so there's noprejudice or biased for one observation over another.Enduring Understanding/Generalization:Frequeny couts, grouped data, serve as pood starting of desripitivestatistically analysis given a data set it gives more structured/ compactanalysis and it easinr /mure convenient to use as compared to ungroupeddata> When oppused to ungroaped tlata, fruuency cuurta, BrOuped data, Jervedas a uselul beginning point for deseriptive statiratically analysis given a datahet. It provideu a more structured/ condensed analysin and is uusier/more

Accepted Answer

Case 1: 50 people are surveyed for full length movies watched in a year. The data has class…