Please give the detailed solution for this problem. I have attached the formulas and the values that are provided to us. Thank you! 2. The equivalent capacitance of two capacitors in series is 0.03 uF and when connected inparallel, 0.16 uF. If the capacitor with the smaller capacitance is replaced with a capacitorwhose capacitance is double as much what will be the new equivalent series capacitance of thecombination. -Ohm's LawVR = p-A^2АVC =VC = EdR =IPermittivity of Common DielectricsL^2R = P:Material.)Air or vacuum0.885Glass (ordinary)7Glass (pyrex)4.7Mica4.8Mylar2.71I aParaffin2R = pАPolyethylene1.99Porcelain6.2Teflon1.9Water @ C70.8Resistivity Coefficients at CResistivity Coefficients at C.m)Capacitor in ParallelMaterialMaterial.m)Silver1.59Carbon3.5xCr = G + C2 + C3Qr = Q1 + Q2 + Q3|CTСopper1.68Germanium0.6Aluminum2.65Silicon2300Tungsten5.6GlassIron9.71LuciteVr = V = V2 = V3Platinum10.6QuartzManganin48.2RubberLead22TeflonMercury98WoodNichrome100Capacitor in SeriesResistors in ParallelResistors in SeriesRr = R1 +R2 + Rg3L = 4 = ½ = I311111+1+11+Cr G'G' CQr = Q1 = Q2 = Q3+Rr R' R2 R3T = 4 +12 +13Vr = V = V2 = V3||%3DVr = V +V½ +V3Vr = V¼ + V½ + V3

Given: let two capacitors areC1 and C2thanCseries =0.03 μFandCparallel =0.16 μF

2. The equivalent capacitance of two capacitors in series is 0.03 uF and when connected in parallel, 0.16 uF. If the capacitor with the smaller capacitance is replaced with a capacitor whose capacitance is double as much what will be the new equivalent series capacitance of the combination.

2. The equivalent capacitance of two capacitors in series is 0.03 uF and when connected in parallel, 0.16 uF. If the capacitor with the smaller capacitance is replaced with a capacitor whose capacitance is double as much what will be the new equivalent series capacitance of the combination.

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 10OQ

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