2. When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The balanced chemical equation is: Pb(NO3)2 (aq) + 2 Nal (aq) → Pbl2 (s) + 2 NaNO3 (aq) a. If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed? b. What is the limiting reagent? c. How many grams of lead (II) iodide is formed? d. If 6 grams of sodium nitrate are actually formed in the reaction described in problem #2, what is the percent yield of this reaction?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 63QRT
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2. When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The
balanced chemical equation is:
Pb(NO:)2 (aq) + 2 Nal (aq) → PbI2 (s) + 2 NaNO3 (aq)
a. If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of
sodium nitrate can be formed?
b. What is the limiting reagent?
c. How many grams of lead (II) iodide is formed?
d. If 6 grams of sodium nitrate are actually formed in the reaction described in problem #2, what is the
percent yield of this reaction?
Transcribed Image Text:2. When lead (II) nitrate reacts with sodium iodide, sodium nitrate and lead (II) iodide are formed. The balanced chemical equation is: Pb(NO:)2 (aq) + 2 Nal (aq) → PbI2 (s) + 2 NaNO3 (aq) a. If I start with 25.0 grams of lead (II) nitrate and 15.0 grams of sodium iodide, how many grams of sodium nitrate can be formed? b. What is the limiting reagent? c. How many grams of lead (II) iodide is formed? d. If 6 grams of sodium nitrate are actually formed in the reaction described in problem #2, what is the percent yield of this reaction?
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