2.3 Experiment 9 - Naming Organic Compounds NH2 CH3 CH CH2 CH NH2 CH3_ CH-CH2-CH-CH3 CH3 CH3 0 CH3 H CH2 CH2 H2CHCI H3CCH2 CH3 CH3 H2N CH2 CH3 OCH2CH2 CH3 The following names are incorrect; correct them CH2 CH3 2-ethylpropane 5-chlorocyclopentene CH3 CH3 CH dimethylcyclohexene 1-methylpropyne 121
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- for the following formulas drew 2 constitutional isomers and provide names in IUPAC for ypur drawings1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the abovereactions and products for C9H8O4 C9H8O4 + O2 --> C9H8O4 + H2O --> C9H8O4 + HCl --> C9H8O4 + OH- --> C9H8O4 + Na --> C9H8O4 + F -->
- Please provide a correct aanswer Answer the following and Identify the reagent (and its concentration) that is used to confirm the presence of each given: a. CO32- b. S2- c. I-Determine the missing product X. 2 HC2H3O2 + K2CO3 --> H2O + 2 KC2H3O2 + X A. X= CO3 2- B. X= H2CO3 C. X= CO2 D. X= K2CO3 E. none of the above.Cembrene, C20H32, is a diterpenoid hydrocarbon isolated from pine resin. Cembrene has a UV absorption at 245 nm, but dihydrocembrene (C20H34), the product of hydrogenation with 1 equivalent of H2, has no UV absorption. On exhaustive hydrogenation, 4 equivalents of H2 react, and octahydrocembrene, C20H40, is produced. On ozonolysis of cembrene, followed by treatment of the ozonide with zinc, four carbonylcontaining products are obtained: Propose a structure for cembrene that is consistent with its formation from geranylgeranyl diphosphate.
- #B: Methyl acetate has methoxy, -OCH3 as the remaining of the alcohol part in the ester. Isopropyl acetate has isopropoxy, -OCH(CH3)2 as the remaining of the alcohol part in the ester. -OCH(CH3)2 is more electron donating than the methoxy, -OCH3 group due to the presence of two electron-donating -CH3 group in the former. Hence saponification reaction of Isopropyl acetate is much slower than methyl acetate. Hence the rate of saponification of methyl acetate, CH3CCO2CH3 is 50 times greater than that for isopropyl acetate.Devise a synthesis of the ketone hexan-3-one, CH3CH2COCH2CH2CH3, from CH3CH2Br as the only organic starting material; that is, all the carbon atoms in hexan-3-one must come from CH3CH2Br. You may use any other neededreagents.Benzene is one of the compounds used as octane enhancers in unleaded gasoline. It is manufactured by thecatalytic conversion of acetylene to benzene: 3C2 H2(g) ⇌ C6 H6(g). Which value of Kc would make this reactionmost useful commercially? Kc ≈ 0.01, Kc ≈ 1, or Kc ≈ 10. Explain your answer
- In the following cases rearrange the compounds as directed : (Delhi 2010)(i) In an increasing order of basic strength :C6H5NH2, C6H5 N(CH3)2, (C2H5)2NH and CH3NH2(ii) In a decreasing order of basic strength :Aniline, p-nitroaniline and p-toluidine(iii) In an increasing order of pKb values :C2H5NH2, C6H5 NHCH3, (C2H5)2NH and C6H5NH2Explain the order of boiling points of the isomeric alcohols but an_1_ol boiling point of 118°C,but an_2_al boiling point of 99°C and 2_methylpropan_2_al boiling point 82°C Menthone and menthal are both isolated from mint ,explain why menthal is a solid at room temperature while menthone is a liquid at room temperature The boiling point of cis _but_2_ene is 3.7°C whereas that of trans_but_2_ene is 0.9°C explainDraw the organic products formed when cyclopentene is treated with each reagent. With some reagents, no reactionoccurs.a. H2 + Pd-Cb. H2 + Lindlar catalystc. Na, NH3d. CH3CO3He. [1] CH3CO3H; [2] H2O, HO–f. [1] OsO4 + NMO; [2] NaHSO3, H2Og. KMnO4, H2O, HO–h. [1] LiAlH4; [2] H2Oi. [1] O3; [2] CH3SCH3j. (CH3)3COOH, Ti[OCH(CH3)2]4, (–)-DETk. mCPBAl. Product in (k); then [1] LiAlH4; [2] H2O