2. Zinc iodide (ZnI2) can be prepared by the direct combination of elements. A chemist determines from the amounts that 0.0654 mol ZnI2 can be formed. How many grams of zinc iodide is this?

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Chapter7: Solutions And Colloids
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1. You need to prepare 2 methanol solutions for lab today: 300mL of 50% (v/v) methanol and 200mL of 25% (v/v) methanol. How much pure methanol is needed to produce 25% given the volume?

2. Zinc iodide (ZnI2) can be prepared by the direct combination of elements. A chemist determines from the amounts that 0.0654 mol ZnI2 can be formed. How many grams of zinc iodide is this?

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