2/0° Α (Y + 1) Ω (W + 3) Ω j2 Ω m 10/90° V j4 Ω Η 4/0°A 31 ΤΩ
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Use mesh analyiss in sloving the problem below
Y=0
W=5
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Solved in 3 steps with 1 images
- What is the total impedance of a 60 Hz series RLC circuit when XL = 7.5 ohms, XC = 265.3 ohms, and R = 33 ohms? A. 257.8 ohms B. 259.9 ohms C. 290.8 ohms D. 1989.75 ohmsIf w=500 rad/s and IL= 2.5 40 degrees find vs(t)Determine x(w) a. x(t) = 10rect(2t)e-j10t b. x(t) = 2+3e-2tu(t) c. x(t) = 10sinc(0.1t)cos(10t)
- Hi is it possible to show solution using mesh analysis instead and taking cosine instead of sine? so Va = 60<0 and Vb = 90<90Find the sum of the voltages and its phase angle and the angle difference of e1=12 sin 10 t + 60oV and e2=6 sin 10 t + 30oV Answer: et= 17.46∠50.10o θpd=30oDetermine f, T, and amplitude for each of the following: a) v(t) = 75 sin(200πt) b) i(t) = 8 sin(300t)
- Do the operation and express the resulting value in rectangular form and in polar form. ( Round-off the resulting values from the computation to the nearest thousandths) 03. [(1–j2)(3–j1)(4+j3)] ÷ [(1–j2)(3–j1) + (3–j1)(4+j3) + (4+j3)(1–j2)]The voltage source vs(t)=200sin(1000t+45°) R = 145 Ω, L = 11 mH, C = 50 µF Calculate the magnitude of the total impedance of the circuit. enter your answer in Ω and round to two decimal places.Find Z_T Please provide answer ASAP I will rate Positively