20) An unknown compound has the chemical formula CH₂O. It's IR spectrum and H NMR spectrum are shown below. Propose a structure for the unknown molecule. Calculate the Degrees of Unsaturation (DU), assign any important peaks in the IR spectrum to vibrational modes and briefly explain why the structure fits the 'H NMR spectrum that is provided Degrees of unsaturation (show work below): 642 Du = (2(3)+2)-6-8-6-2²/1/2 = 1 2 3437 1739 16-o mpy m Vibrational Assignments of IR Peaks Wavenumber (cm-¹) Vibrational Assignment 2 0-4 stretch C=0 strekn Peak 1: 9.79 ppm 1H Singlet 9 8 Brief rationalization for proposed structure: (explain why DU, IR, and NMR are consistent with proposed structure) ppm Peak 2 2.45 ppm 2H Quartet Peak 3 1.11 ppm 3H Triplet Proposed structure of unknown:

Organic Chemistry
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Chapter21: Benzene And The Concept Of Aromaticity
Section: Chapter Questions
Problem 21.20P
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20) An unknown compound has the chemical formula CH₂O. It's IR spectrum and ¹H NMR
spectrum are shown below. Propose a structure for the unknown molecule. Calculate the
Degrees of Unsaturation (DU), assign any important peaks in the IR spectrum to vibrational
modes and briefly explain why the structure fits the 'H NMR spectrum that is provided
Degrees of unsaturation (show work below):
442
Du= (2(3)+2)-6
2
-8-16 - 2²/2/2 = 1
3437
1739
Amply
0
Vibrational Assignments of IR Peaks
Wavenumber (cm-¹) Vibrational Assignment
0-4 stretch
6=0 strekh
Peak 1:
9.79 ppm
14
Singlet
3
8
Brief rationalization for proposed structure: (explain why DU, IR, and
NMR are consistent with proposed structure)
ppm
Peak 2
2.45 ppm
2H
Quartet
Peak 3
1.11 ppm
3H
Triplet
D
Proposed structure of unknown:
Transcribed Image Text:20) An unknown compound has the chemical formula CH₂O. It's IR spectrum and ¹H NMR spectrum are shown below. Propose a structure for the unknown molecule. Calculate the Degrees of Unsaturation (DU), assign any important peaks in the IR spectrum to vibrational modes and briefly explain why the structure fits the 'H NMR spectrum that is provided Degrees of unsaturation (show work below): 442 Du= (2(3)+2)-6 2 -8-16 - 2²/2/2 = 1 3437 1739 Amply 0 Vibrational Assignments of IR Peaks Wavenumber (cm-¹) Vibrational Assignment 0-4 stretch 6=0 strekh Peak 1: 9.79 ppm 14 Singlet 3 8 Brief rationalization for proposed structure: (explain why DU, IR, and NMR are consistent with proposed structure) ppm Peak 2 2.45 ppm 2H Quartet Peak 3 1.11 ppm 3H Triplet D Proposed structure of unknown:
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