20. 2NaHCO3(s) Na,CO3(s) + H20(g) + CO2(g), Kp(300 °C) = 1.55 atm², AH°rxn = +136 kJ 1) Write the formulas for Kp and Qp of this equation: Kp = Qp = 2) A mixture of NaHCO3(s), Na2CO3(s) under 1.12 atm CO2(g) and 1.38 atm H20(g) has Qp = To reach equilibrium, it will shift to: (show direction) 3) When a sample of NaHCo3(s) alone is heated in a sealed volume at 300 °C, it comes to equilibrium with Kp(300 °C) = 1.55 atm?, Pea(CO2) = atm, Peg(H20) = atm, and the total P = atm.
20. 2NaHCO3(s) Na,CO3(s) + H20(g) + CO2(g), Kp(300 °C) = 1.55 atm², AH°rxn = +136 kJ 1) Write the formulas for Kp and Qp of this equation: Kp = Qp = 2) A mixture of NaHCO3(s), Na2CO3(s) under 1.12 atm CO2(g) and 1.38 atm H20(g) has Qp = To reach equilibrium, it will shift to: (show direction) 3) When a sample of NaHCo3(s) alone is heated in a sealed volume at 300 °C, it comes to equilibrium with Kp(300 °C) = 1.55 atm?, Pea(CO2) = atm, Peg(H20) = atm, and the total P = atm.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter17: Spontaneity, Entropy, And Free Energy
Section: Chapter Questions
Problem 118CP: Consider the reaction H2(g)+Br2(g)2HBr(g) where H = 103.8 kJ/mol. In a particular experiment, equal...
Related questions
Question
Transcribed Image Text:20. 2NaHCO3(s)
Na,CO3(s) + H20(g) + CO2(g), Kp(300 °C) = 1.55 atm², AH°rxn = +136 kJ
1) Write the formulas for Kp and Qp of this equation: Kp =
Qp =
2) A mixture of NaHCO3(s), Na2CO3(s) under 1.12 atm CO2(g) and 1.38 atm H20(g)
has Qp =
To reach equilibrium, it will shift to:
(show direction)
3) When a sample of NaHCo3(s) alone is heated in a sealed volume at 300 °C, it comes to
equilibrium with Kp(300 °C) = 1.55 atm?, Reg(CO2) =
atm, Peg(H20) =
atm,
and the total P =
atm.
4) If the mixture at equilibrium is compressed in volume by half at 300 °C, the total pressure at
the new equilibrium will be
atm
5) If the mixture at equilibrium is cooled, it will shift to:
(show direction). The total
pressure at the new equilibrium will be: higher ? lower ? same as before (circle one)
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning