20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a rectangular contracted weir 85cm high should be placed in the middle of the canal if the depth of water upstream is to be 1.20m? Given:

Structural Analysis
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Chapter2: Loads On Structures
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Need asap. On the red box, What is that formula ? It is not orifice problem but why there is Ao. Can you put the exact formula? Thank you
20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries
water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a
rectangular contracted weir 85cm high should be placed in the middle of
the canal if the depth of water upstream is to be 1.20m?
Given:
Find: L =?
H
d=1.20m
P = 0.85
do = 0.40m
H = 1-20-0-85
H = 6.35
original w.s
2,4m
Solution:
L' = 4.28 m
GM
= ½ (6 + 7.6) (0.4) (0.6)
= 1.63m3/s
Q = 1.84 L'H 3/2
1.63 = 1.84 L' (0.35) 3/2
Qo = AoVo
*aam
L = 4.28 +0.20(0.35)
L = 4.35m
Transcribed Image Text:20. A trapezoidal canal, 6m at the bottom and having side slopes 2:1 carries water to a depth of 40cm and mean velocity of 0.60 m/s. what length of a rectangular contracted weir 85cm high should be placed in the middle of the canal if the depth of water upstream is to be 1.20m? Given: Find: L =? H d=1.20m P = 0.85 do = 0.40m H = 1-20-0-85 H = 6.35 original w.s 2,4m Solution: L' = 4.28 m GM = ½ (6 + 7.6) (0.4) (0.6) = 1.63m3/s Q = 1.84 L'H 3/2 1.63 = 1.84 L' (0.35) 3/2 Qo = AoVo *aam L = 4.28 +0.20(0.35) L = 4.35m
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