-200 2 Fe + 0, →2 F 2C+02-2 CO -300 -400 -500 -600 -700 4/3 Al + 0, → 2/3 Al,0, -1000 -800 -900 -1100 2 Mg + 0, → 2 MgO -1200 0 400 800 1200 1600 AG° (kJ/mole O2)
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- In Active Example 3-29 you calculated that you would have to work six weeks to earn enough money to buy a 1082.49 television. You would be working five shifts of four hours each at 9.25/hr. But, alas, when you received your first pay check, you found that exactly 23 of your earnings had been withheld for social security, federal and state income taxes, and workers compensation insurance. Taking these into account, how many weeks will it take to earn the 1082.49?Chemistry (i) For T = 298K ΔG° = -8.314 x 298 x ln (2.83x10-3) = 14.524 KJ/mol (ii) For T = 308.15K ΔG° = -8.314 x 308.15 x ln (9.619x10-3) = 11.891 KJ/mol (iii) For T = 318.15K ΔG° = -8.314 x 318.15 x ln (3.14x10-2) = 9.147 KJ/mol (iv) For T = 328.15K ΔG° = -8.314 x 328.15 x ln (8.82x10-2) = 6.621 KJ/mol (v) For T = 338.15K ΔG° = -8.314 x 338.15 x ln (2.42x10-1) = 3.990 KJ/mol Based on the measured ΔG° values, is this equilibrium spontaneous at room temperature? Which factor, entropy, or enthalpy, has the greater impact on spontaneity in this case? Explain your answers.A pipet is used to transfer 6.00 mLmL of a 3.75 MM stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2OH2O to the calibration mark. The solution is thoroughly mixed. Next, 10.00 mLmL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2OH2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
- A volumetric calcium analysis on triplicate samples of the blood serum of a patient believed to be suffering from a hyperparathyroid condition produced the following data: mmol Ca/L = 3.15, 3.25, 3.26. What is the 95% confidence interval for the mean of the data, assuming no prior information about the precision of the analysis?Beaker 0.00200 M Fe(NO3)3, mL 0.00200 M NaSCN, mL total volume, mL 1 3.000 2.000 10.00 2 3.000 3.000 10.00 3 3.000 4.000 10.00 4 3.000 5.000 10.00 5 (blank) 3.000 0.000 10.00 In Solutions 1-4 you are adding successively larger volumes of 0.00200M SCN- to the Fe3+ solution and diluting to 10.00 ml. Calculate the final diluted molarity of SCN- in solution #1 Your answer should have 3 sig figs =Tonya sold 160 sandwiches for $2.00 each. Each sandwich consisted of 4 oz of ham, two slices of bread, and mustard. She paid $3.00/lb for the ham, $0.60/loaf for the bread and used 8 jars of mustard at $0.50 each. How much profit did she make? Note: I attempted the problem, but it felt like I was going about it wrong. It’s for a chem class, but is there a less conveluded algebraic way to solve it? Or other method?
- NSCI- Chemistry Answer only 1-3Stock iron(II) solution (200Ug mL-1 Fe) ferrous ammonium sulfate hexahydrate mass= 0.1437g, transfer it to a 100 ml beaker. add 15 ml approx of water and 15m1 'approx of dilute sulphuric acid (2M H2SO.). then transfer FeII to 100 ml flask makeup to the mark with water. calculate the moles of ferrous ammonium sulfate hexahydrate solution in unit ug/mL.A pipet is used to transfer 5.00 mL of a 1.25 M stock solution in flask “S” to a 25.00-mL volumetric flask “B,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”
- A pipet is used to transfer 3.00 mL of a 2.00 M stock solution in flask “S” to a 25.00-mL volumetric flask “A,” which is then diluted with DI H2O to the calibration mark. The solution is thoroughly mixed. Next, 3.00 mL of the solution in volumetric flask “A” is transferred by pipet to a 50.00-mL volumetric flask “B” and then diluted with DI H2O to the calibration mark. Calculate the molarity of the solution in volumetric flask “B.”Ksp = 1.5x10^-11 for Mg(OH)22 CoCl2(aq) + 8 NH3(aq) + H2O2(aq) + 2 NH4Cl(aq) 2 [Co(NH3)5Cl]Cl2(s) + 2 H2O(l) In a 50-mL Erlenmeyer flask, cobalt(II) chloride hexahydrate (1.075 g), an aqueous solution of ammonia (1.2 mL, 15 M), ammonium chloride (0.505 g), and hydrogen peroxide (1.0 mL, 30.0% (w/w), density = 1.10 g/mL) were combined. After completion of the reaction, [Co(NH3)5Cl]Cl2 (0.450 g) was isolated. What was the percent yield of the product?