200 A Moving to another question will save this response. Question 14 of 20 Question 14 1 points Save Answer A car is travelling at the speed of V m/s on a straight, level road. After the brakes are applied at t = 0, the motion can be approximated by s = (1/100)(t^3) - t^2 + 20t, where s is the distance traveled in meters, and t is the time in seconds. Determine the distance (meters) required for the car to stop. Round off to one decimal place.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter2: Motion In One Dimension
Section: Chapter Questions
Problem 18P: A race car moves such that, its position fits the relationship x = (5.0 m/s)t + (0.75 m/s3)t3 where...
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A car is travelling at the speed of V m/s on a straight, level road. After the brakes are applied at t = 0, the motion can be approximated by s = (1/100)(t^3) -
t^2 + 20t, where s is the distance traveled in meters, and t is the time in seconds. Determine the distance (meters) required for the car to stop. Round off
1 points
to one decimal place.
A Moving to another question will save this response.
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Transcribed Image Text:200 A Moving to another question will save this response. Question 14 Question 14 of 20 Save Answer A car is travelling at the speed of V m/s on a straight, level road. After the brakes are applied at t = 0, the motion can be approximated by s = (1/100)(t^3) - t^2 + 20t, where s is the distance traveled in meters, and t is the time in seconds. Determine the distance (meters) required for the car to stop. Round off 1 points to one decimal place. A Moving to another question will save this response. «< Question 14 of 20 29°C Rain sho... O G EN F11 untk DIO 64 Coca ) R
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