22 only Find an absolute velocity and acceleration of Particle M at time t=t1 if relative motion of M and rotational motion of body D are given.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Find an absolute velocity and acceleration of Particle M at time t=t1 if relative motion of M and rotational motion of body D are given. 

%3D
R
Pe
Figure 6.22.
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Transcribed Image Text:%3D R Pe Figure 6.22. MI
DETERMINATION OF ABSOLUTE VELOCITY AND ABSOLUTE
ACCELERATION OF PARTICLE IN ROTATIONAL TRANSFER MOTION
6.1
Find an absolute velocity and acceleration of particle M at time t = t, if relative motion of M and rotational motion
of body D are given. All mechanisms are schematically shown in Figures 6.1-6.30, and the necessary information is
given in the table below.
Problem
ゆe=f(),
OM = S, = f2(1),
#3
rad
t1, S
R, ст
а, ст
a, deg
ст
voda
1
213 -12
18 sin t
2/3
25
0.4 2 +t
20 sin at
5/3
20
2t + 0.512
613
30
0.62
10 sin
4
1
60
3t + 0.513
40n cos t
COS
30
6.
0.75t+ 1.52
150t2
1/6
25
7.
0.52
20 cos 2nt
3/8
40
60
8.
B-0.5t
6(t + 0.5t2)
30
9.
4t + 1.61
10 + 10 sin 2nt
1/8
20T Cos t
10
1.2t – 12
4/3
20
20
-
212 - 0.5t
25 sin t
4
25
30 -
(15/8) T³
120 π/
12
5t - 42
30
13
82- 3t
1/3
40
14
4t – 212
3+ 14 sinat
2/3
30
0.213+t
5 V2 (2 + 1)
15
60
45
16
t-0.5 2
20 sinzt
1/3
20
17
0.512
813 + 2t
1
4
18
8t- 12
10t + 3
60
19
t+312
6t + 43
40
TC
30п сos
60
20
6t + t2
2t - 412
25T(t + t2)
1/2
25
21
10π sin /
TC
4
2/3
30
22
4t - 0.22
30
312+ 4t
23
2t – 0.2512
2.
3.
23
11
Transcribed Image Text:DETERMINATION OF ABSOLUTE VELOCITY AND ABSOLUTE ACCELERATION OF PARTICLE IN ROTATIONAL TRANSFER MOTION 6.1 Find an absolute velocity and acceleration of particle M at time t = t, if relative motion of M and rotational motion of body D are given. All mechanisms are schematically shown in Figures 6.1-6.30, and the necessary information is given in the table below. Problem ゆe=f(), OM = S, = f2(1), #3 rad t1, S R, ст а, ст a, deg ст voda 1 213 -12 18 sin t 2/3 25 0.4 2 +t 20 sin at 5/3 20 2t + 0.512 613 30 0.62 10 sin 4 1 60 3t + 0.513 40n cos t COS 30 6. 0.75t+ 1.52 150t2 1/6 25 7. 0.52 20 cos 2nt 3/8 40 60 8. B-0.5t 6(t + 0.5t2) 30 9. 4t + 1.61 10 + 10 sin 2nt 1/8 20T Cos t 10 1.2t – 12 4/3 20 20 - 212 - 0.5t 25 sin t 4 25 30 - (15/8) T³ 120 π/ 12 5t - 42 30 13 82- 3t 1/3 40 14 4t – 212 3+ 14 sinat 2/3 30 0.213+t 5 V2 (2 + 1) 15 60 45 16 t-0.5 2 20 sinzt 1/3 20 17 0.512 813 + 2t 1 4 18 8t- 12 10t + 3 60 19 t+312 6t + 43 40 TC 30п сos 60 20 6t + t2 2t - 412 25T(t + t2) 1/2 25 21 10π sin / TC 4 2/3 30 22 4t - 0.22 30 312+ 4t 23 2t – 0.2512 2. 3. 23 11
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