23.51 Determining the Size of the Nucleus. Whenradium-226 decays radioactively, it emits an alpha particle (thenucleus of helium), and the end product is radon-222. We canmodel this decay by thinking of the radium-226 as consisting ofan alpha particle emitted from the surface of the spherically symmetric radon-222 nucleus, and we can treat the alpha particle as apoint charge. The energy of the alpha particle has been measuredin the laboratory and has been found to be 4.79 MeV when thealpha particle is essentially infinitely far from the nucleus. Sinceradon is much heavier than the alpha particle, we can assume thatthere is no appreciable recoil of the radon after the decay. Theradon nucleus contains 86 protons, while the alpha particle has2 protons and the radium nucleus has 88 protons. (a) What wasthe electric potential energy of the alpha-radon combination justbefore the decay, in MeV and in joules? (b) Use your resultpart (a) to calculate the radius of the radon nucleus

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23.51 Determining the Size of the Nucleus. When
radium-226 decays radioactively, it emits an alpha particle (the
nucleus of helium), and the end product is radon-222. We can
model this decay by thinking of the radium-226 as consisting of
an alpha particle emitted from the surface of the spherically sym
metric radon-222 nucleus, and we can treat the alpha particle as a
point charge. The energy of the alpha particle has been measured
in the laboratory and has been found to be 4.79 MeV when the
alpha particle is essentially infinitely far from the nucleus. Since
radon is much heavier than the alpha particle, we can assume that
there is no appreciable recoil of the radon after the decay. The
radon nucleus contains 86 protons, while the alpha particle has
2 protons and the radium nucleus has 88 protons. (a) What was
the electric potential energy of the alpha-radon combination just
before the decay, in MeV and in joules? (b) Use your result
part (a) to calculate the radius of the radon nucleus
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23.51 Determining the Size of the Nucleus. When radium-226 decays radioactively, it emits an alpha particle (the nucleus of helium), and the end product is radon-222. We can model this decay by thinking of the radium-226 as consisting of an alpha particle emitted from the surface of the spherically sym metric radon-222 nucleus, and we can treat the alpha particle as a point charge. The energy of the alpha particle has been measured in the laboratory and has been found to be 4.79 MeV when the alpha particle is essentially infinitely far from the nucleus. Since radon is much heavier than the alpha particle, we can assume that there is no appreciable recoil of the radon after the decay. The radon nucleus contains 86 protons, while the alpha particle has 2 protons and the radium nucleus has 88 protons. (a) What was the electric potential energy of the alpha-radon combination just before the decay, in MeV and in joules? (b) Use your result part (a) to calculate the radius of the radon nucleus

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a)

The required potential energy of the...

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U(4.79x10ev1.6x10"J leV 7.664 x10

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