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232 Th - 228 Th + xa + yB 90 06 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 2, y = 2 O x = 1, y = 1 O x = 1, y = 2 O x = 2, y = 1

232 Th - 228 Th + xa + yB 90 06 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 2, y = 2 O x = 1, y = 1 O x = 1, y = 2 O x = 2, y = 1

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter24: Nuclear Chemistry
Section: Chapter Questions
Problem 89A
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232 Th 90 228 Th+ χα + yβ 90 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 2, y = 2 O x = 1, y = 1 O x = 1, y = 2 O x = 2, y = 1
Transcribed Image Text:232 Th 90 228 Th+ χα + yβ 90 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 2, y = 2 O x = 1, y = 1 O x = 1, y = 2 O x = 2, y = 1
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