232 Th 228. Th + xa + yB 06 90 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 1, y = 2 O x = 2, y = 2 O x = 2, y = 1 O x = 1, y = 1

Principles of Physics: A Calculus-Based Text
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Chapter30: Nuclear Physics
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232
Th
90
228 Th + xa + yB
90
A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y.
O x = 1, y = 2
O x = 2, y = 2
O x = 2, y = 1
O x = 1, y = 1
Transcribed Image Text:232 Th 90 228 Th + xa + yB 90 A Thorium (Th) decays by emitting x alpha particles and y beta particles to form an isotope of the original nuclide as shown in above reaction. Find the values of x and y. O x = 1, y = 2 O x = 2, y = 2 O x = 2, y = 1 O x = 1, y = 1
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