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- Question 2.1 Given a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows: If N is an even number, then divide N by twoto get a new value for N If N is an odd number, then multiply N by 3 and add 1to get a new value for N. Continue to generate numbers in thisway until N becomes equal to 1 For example, starting from N = 3 the complete ’3N+1’ sequence would be: 3, 10, 5, 16, 8, 4, 2, 1 Write code to ask the user to enter a positive integer (N)in the main()function. Write a function sequence() that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that was received (entered by the user). The function must also count and return the numbers that the sequence consists of. Thereturned value must be displayed from the main() function. Question 2.2 Write a function createPassword()with no return value to randomly select 8 capital letters from the alphabet. The function receives the address of the first characters of the…Scylla or Charybdis? def scylla_or_charybdis(moves, n): This problem was inspired by the article "A Magical Answer to the 80-Year-Old Puzzle" in Quanta Magazine. Thanks to your recent cunning stunts, your nemesis in life is trapped inside a devious game where, for a refreshing change from the usual way of things, you get to be the Final Boss. (Everyone is the hero in their own story until they become a villain in somebody else's, after all.) This final level is a one-dimensional video game platform that reaches n-1 steps from its center to both directions. At each end of this platform exactly n steps away from the center, your two lethal friends Scylla and Charybdis are licking their lips in anticipation of a tasty morsel. Your nemesis starts at the center of this platform. To start this deadly combat of wits, she must immediately commit to her entire sequence of future moves, given to this function as a string of characters '+' (“� just a step to the ri-i-i-i-ight � ”) and '-' (move…Problem 4: Magic Square Test A magic square of order n is an arrangement of n × n numbers, usually distinct integers, in a square, such that the n numbers in all rows, all columns, and both diagonals sum to the same constant. See all rows’, columns’ and diagonal’s sum is same. Write a main method where first you need to input n. Then input n*n integers and form a 2D matrix. Print “YES” if the matrix is magic square and print “NO” Otherwise. Sample input: 3 2 7 6 9 5 1 4 3 8 Output: YES
- Artificial Intelligence - Local Search Starting from a randomly generated state of the 15-puzzle game, steepest-ascent hill-climbing (the vanilla version of hill-climbing search) gets stuck 76% of the time, i.e., solving only 24% of problem instances. But it works very quickly, i.e., it takes just 6 steps on average when it succeeds and 5 steps when it gets stuck. In contrast, if sideways moves are allowed, this raises the percentage of problem instances solved by hill-climbing from 24% to 81%, with the success at a cost: the algorithm averages roughly 7 steps for each successful instance and 32 steps for each failure. Now suppose that we are implementing random-restart hill climbing (i.e., if a search fails, it keeps to try, and try, until it gets a success) by the following two versions: one uses vanilla steepest-ascent hill climbing, and the other one uses hill climbing with sideways moves. Can you please tell which version of random-restart hill-climbing listed above runs faster…Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2 we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…Let p, q, and r be the propositions p: You started a new video game this week. q: You finished all its quests.r: You didn’t win the platinum trophy.Express each of these propositions as an English sentence.¬p → ¬q(p ∧ q) → (¬r)((¬p) → (¬q)) ∨ (q → (¬r))(p ∧ q) ∨ (¬q ∧ r)
- Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. Ridbit begins with an integer n. In one action, he can perform one of the accompanying tasks: partition n by one of its appropriate divisors, or take away 1 from n in case n is more prominent than 1. An appropriate divisor is a divisor of a number, barring itself. For instance, 1, 2, 4, 5, and 10 are appropriate divisors of 20, however 20 itself isn't. What is the base number of moves Ridbit is needed to make to decrease n to 1? Input The principal line contains a solitary integer t (1≤t≤1000) — the number of experiments. The main line of each experiment contains a solitary integer n (1≤n≤109). Output For each experiment, output the base number of moves needed to lessen n to 1.JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…You will be given a square chess board with one queen and a number of obstacles placed on it. Determine how many squares the queen can attack. A queen is standing on an chessboard. The chess board's rows are numbered from to , going from bottom to top. Its columns are numbered from to , going from left to right. Each square is referenced by a tuple, , describing the row, , and column, , where the square is located. The queen is standing at position . In a single move, she can attack any square in any of the eight directions (left, right, up, down, and the four diagonals). In the diagram below, the green circles denote all the cells the queen can attack from : There are obstacles on the chessboard, each preventing the queen from attacking any square beyond it on that path. For example, an obstacle at location in the diagram above prevents the queen from attacking cells , , and : Given the queen's position and the locations of all the obstacles, find and print the number of…
- please help me with the following 1) make a sierpenski triangle using java and recursion. Make it similar to the code below. And please comment the code 2) Please make the follow code out put on the console. It a t square fractal import java.awt.image.*;import java.awt.Color;import java.io.*;import javax.imageio.*; public class Main{ static final int DIMENSION = 1000; static BufferedImage image = new BufferedImage(DIMENSION, DIMENSION, BufferedImage.TYPE_INT_RGB); static final int WHITE = Color.WHITE.getRGB(); static final int BLACK = Color.BLACK.getRGB(); private static void drawSquare(int x, int y, int side) { if (side <= 0) return; else { int left = x - side/2; int top = y - side/2; int right = x + side/2; int bottom = y + side/2; for (int i = left; i < right; i++) for (int j = top; j < bottom; j++) { image.setRGB(i, j, BLACK); }…A popular word game involves finding words from a grid of randomly generatedletters. Words must be at least three letters long and formed from adjoining letters.Letters may not be reused and it is valid to move across diagonals. As an example,consider the following 4 * 4 grid of letters: A B C DE F G HI J K LM N O P The word “FAB” is valid (letters in the upper left corner) and the word “KNIFE”is valid. The word “BABE” is not valid because the “B” may not be reused. Theword “MINE” is not valid because the “E” is not adjacent to the “N”. Write a program that uses a 4 * 4 two-dimensional array to represent the gameboard. The program should randomly select letters for the board. You may wishto select vowels with a higher probability than consonants. You may also wish toalways place a “U” next to a “Q” or to treat “QU” as a single letter. The programshould read the words from the text file words.txt (included on the website withthis book) and then use a recursive algorithm to…Chat GPT answers will be reported. AI software will be reported. Do not copy answers from elsewhere, work manually. Consider the DFA M = (Q,Σ,δ,q1,F) where Q = {q1,q2,q3,q4},Σ = {a,b},F = {q4} andδ(q1,a) = q2,δ(q2,b) = q3,δ(q3,a) = q4,δ(q3,b) = q1.Convert this DFA to a regular expression using the method discussed in class (as this automaticallyproves that the answer is correct, as the algorithm is proven correct). You only need to calculate sub-expressions if it is necessary towards the final answer. Also, simplify each subexpression using any lawdiscussed in class (including those derived on the board). To summarize, those were 1) (ε+ R)∗= R∗,2) S ·R∗= R∗if L(S) ⊆L(R∗) and ε ∈S, and 3) S + R = R if L(S) ⊆L(R).