Question
Asked Nov 3, 2019
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23U (atoic mass 238.050784 u) decays via alpha decay to 234Th (atomic mass 234.043593 u).
What is the kinetic energy of the emitted alpha particle? Assume the uranium nucleus was initially
at rest (so the initial momentum was zero).
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23U (atoic mass 238.050784 u) decays via alpha decay to 234Th (atomic mass 234.043593 u). What is the kinetic energy of the emitted alpha particle? Assume the uranium nucleus was initially at rest (so the initial momentum was zero).

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Expert Answer

Step 1

Alpha-decay of  238uranium is shown by equation (1)

Mass of uranium atom =238.0507785 u

Mass of thorium atom =234.043594 u

Mass of alpha-particles = 4.002603 u

 

Q-value for this reaction

 

 

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234Th+4He 90 238U 92 (1) (2) Q-value-931.5 m,-mr MeV =-931.5(234.043594+4.002603-238.0507785) MeV = 4.274 MeV

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Step 2

It is given that the initial momentum of uranium is zero.

According to the conservation of momentum law-

As momentum  (P) = mass × velocity

Als...

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PU PThPHe - Рrh-Pне 0 P ThHe =P Th (3) MThVть МНе'Не V. =__Th 'Th 4) "Не М, Не Kinetic energy (k.E)=mv2 K.E (He)2mHe"He) (5) 2 Th'Th mHe K.E(He m 2" Не Th 2 Th Th (Не Th -Κ.Ε (Th (Не K.Е(Не) 234.043594 (6) 4.002603 Κ.Ε (Th)

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Chemistry

Atomic structure

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