24. NEMA-rated general-purpose motors can operate on voltages 610% of their rated nameplate voltage. An unbalanced voltage situation is extremely damaging to a motor. Calculate the expected heat rise in a motor subjected to an unbalanced voltage situation where the voltages between phases AB = 465 volts, BC = 487 volts, and CA = 473 volts. Add these voltages: Total Find the average voltage: Total ÷ 3 = volts Full Subtract the average voltage from the voltage reading that results in the greatest difference: volts 100 ÷ Greatest voltage difference/Average voltage = %voltage unbalance Temperature rise in the winding with highest current = 2 × (percent voltage unbalance)? % temperature rise in the winding with highest current

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter34: Motor Installation
Section: Chapter Questions
Problem 6PP: A 350-HP squirrel-cage induction motor is connected to a 480-volts three-phase feeder. The nameplate...
icon
Related questions
Question
24. NEMA-rated general-purpose motors can operate on voltages 610% of their rated nameplate voltage. An unbalanced voltage situation is extremely damaging to a
motor. Calculate the expected heat rise in a motor subjected to an unbalanced voltage situation where the voltages between phases AB = 465 volts, BC = 487 volts,
and CA = 473 volts.
Add these
voltages:
Total
Find the average voltage: Total ÷ 3 =
volts
Full Bool
Subtract the average voltage from the voltage reading that results in the greatest difference:
volts
100 ÷ Greatest voltage difference/Average voltage =
%voltage unbalance
Temperature rise in the winding with highest current = 2 x (percent voltage unbalance)2
% temperature rise in
the winding with highest current
File Upload
Transcribed Image Text:24. NEMA-rated general-purpose motors can operate on voltages 610% of their rated nameplate voltage. An unbalanced voltage situation is extremely damaging to a motor. Calculate the expected heat rise in a motor subjected to an unbalanced voltage situation where the voltages between phases AB = 465 volts, BC = 487 volts, and CA = 473 volts. Add these voltages: Total Find the average voltage: Total ÷ 3 = volts Full Bool Subtract the average voltage from the voltage reading that results in the greatest difference: volts 100 ÷ Greatest voltage difference/Average voltage = %voltage unbalance Temperature rise in the winding with highest current = 2 x (percent voltage unbalance)2 % temperature rise in the winding with highest current File Upload
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Three phase Induction Motor
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
EBK ELECTRICAL WIRING RESIDENTIAL
EBK ELECTRICAL WIRING RESIDENTIAL
Electrical Engineering
ISBN:
9781337516549
Author:
Simmons
Publisher:
CENGAGE LEARNING - CONSIGNMENT