24. Which of the following statements deletes the first node of a linear linked list that has 10 nodes? a. head->next - cur->next; c. prev->next - cur->next; d. head b. head head->next; NULL;
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- Complete the following function where a node is perculated through a MaxHeap when given the value of the parent node (through the use of a linked list) void BinMaxHeap::percolateUp(BHNode *p) { }Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next; } Write a function which concatenates two non-empty linked lists. Its exact signature should be: void concat(NodeInt32* headA, NodeInt32* headB); After execution, the tail of headA should point to headB. The skeleton file is belowPlease code in C language. Please use the starter code to help you solve the deleted node and the reverse list. Here is the starter code: #include <stdio.h> #include <ctype.h> #include <stdlib.h> #include <string.h> #include "linkedlist.h" // print an error message by an error number, and return // the function does not exit from the program // the function does not return a value void error_message(enum ErrorNumber errno) { char *messages[] = { "OK", "Memory allocaton failed.", "Deleting a node is not supported.", "The number is not on the list.", "Sorting is not supported.", "Reversing is not supported.", "Token is too long.", "A number should be specified after character d, a, or p.", "Token is not recognized.", "Invalid error number."}; if (errno < 0 || errno > ERR_END) errno = ERR_END; printf("linkedlist: %s\n", messages[errno]); } node *new_node(int v) { node *p =…
- what is the problem in the display function ? the code : #include <iostream>using namespace std; class node{public: int data; node* next;}; void display(node * head) // printing the data of the nodes{ node* temp = head; while (temp != NULL) { cout << temp->data << endl; temp = temp->next; }} // add void push(node** head, int newdata) // { 5, 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = *head; *head = newnode;} void append(node** head, int newdata) // { 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = NULL; node* last = *head; if (*head == NULL) { *head = newnode; return; } while (last->next != NULL) { last = last->next; } last->next = newnode;} void insertafter(node*…C++ What is the output of following function for start pointing to first node of following linked list? 1->2->3->4->5->6 void fun(Node<ItemType>* start) { if(start == nullptr) return; cout << start->getItem() << " "; if(start->getNext() != nullptr ) fun(start->getNext()->getNext()); cout << start->getItem() << " ";} eof.C++ Given code #include <iostream>using namespace std; class Node {public:int data;Node *pNext;}; void displayNumberValues( Node *pHead){while( pHead != NULL) {cout << pHead->data << " ";pHead = pHead->pNext;}cout << endl;} //Option 1: Search the list// TODO: complete the function below to search for a given value in linked lsit// return true if value exists in the list, return false otherwise. ?? linkedlistSearch( ???){ } //Option 2: get sum of all values// TODO: complete the function below to return the sum of all elements in the linked list. ??? getSumOfAllNumbers( ???){ } int main(){int userInput;Node *pHead = NULL;Node *pTemp;cout<<"Enter list numbers separated by space, followed by -1: "; cin >> userInput;// Keep looping until end of input flag of -1 is givenwhile( userInput != -1) {// Store this number on the listpTemp = new Node;pTemp->data = userInput;pTemp->pNext = pHead;pHead = pTemp;cin >> userInput;}cout <<"…
- Topic: Singly Linked ListImplement the following functions in C++ program. Read the question carefully. (See attached photo for reference) void isEmpty() This method will return true if the linked list is empty, otherwise return false. void clear() This method will empty your linked list. Effectively, this should and already has been called in your destructor (i.e., the ~LinkedList() method) so that it will deallocate the nodes created first before deallocating the linked list itself.struct node{ int a; struct node * nextptr; }; Write two functions. One for inserting new values to a link list that uses the given node structure. void insert(struct node **head, int value); Second function is called to count the number of even numbers in the link list. It returns an integer that represents the number of even numbers. int countEvenNumbers(struct node *head); Write a C program that reads a number of integers from the user and insert those integers into a link list (use insert function). Later pass the head pointer of this link list to a function called countEvenNumbers. This function counts and returns the number of even numbers in the list. The returned value will be printed on the screen. Note 1: Do not modify the function prototypes. Sample Input1: Sample Output1: 45 23 44 12 37 98 33 35 -1 3 Sample Input2: Sample Output2: 11 33 44 21 22 99 123 122 124 77 -1 4Having trouble with creating the InsertAtEnd function in the ItemNode.h file below. " // TODO: Define InsertAtEnd() function that inserts a node // to the end of the linked list" Given main(), define an InsertAtEnd() member function in the ItemNode class that adds an element to the end of a linked list. DO NOT print the dummy head node. Ex. if the input is: 4 Kale Lettuce Carrots Peanuts ------------------------------------------------------- main.cpp -------------------------------------------------------- #include "ItemNode.h" int main() { ItemNode *headNode; // Create intNode objects ItemNode *currNode; ItemNode *lastNode; string item; int i; int input; // Front of nodes list headNode = new ItemNode(); lastNode = headNode; cin >> input; for (i = 0; i < input; i++) { cin >> item;…
- What does this part of code do? void addRecord(Node *& head, Node *& tail, string name, double balance){ Node *newNode = new Node; newNode->name = name; newNode->balance = balance; newNode->next = NULL; newNode->prev = NULL; // If list is empty, make newNode the first node if(head == NULL){ head = newNode; tail = newNode; } else{ Node *temp = head; // Loop through list until temp->next is NULL while(temp->next != NULL){ temp = temp->next; } temp->next = newNode; newNode->prev = temp; tail = newNode; }} /*Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next;} Write a function which searches a non-empty linked list for a target value. Its exact signature should be: NodeInt32* find(NodeInt32* head, int32_t target); The function should return the first node whose value equals target. If the target is not found in the list, then the function should return NULL.int F(node<int>&p){int c=0; while(p!=0){p=p->next; c++; } return c;} This function is a. return the number of items in the linked list b. return the number of items in a linked list and destroy the linked list c. None of these d. destroy the list and free all allocated nodes