25-27. A current of 10.0 A flows through a rod of length 0.20 m placed perpendicularly across a magnetic field of 0.050 T. or Show that the magnetic force on the rod is 0.10 N. i

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter24: Magnetic Fields
Section24.2: Forces Caused By Magnetic Fields
Problem 27PP
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Need help with this workbook 25-27 problem. Thank you. I will give thumbs up. 

ool sef
moving at 600 m/s with charge of 20 uC enters a magnetic field of 1.6 T and
reases at a
ced in the
is swept into a circular arc of radius 225 m.
o Show that the mass of the particle is 12 milligrams. 1 0
25-27. A current of 10.0 A flows through a rod of length 0.20 m placed perpendicularly
across a magnetic field of 0.050 T.
Show that the magnetic force on the rod is 0.10 N.omie , 160
Transcribed Image Text:ool sef moving at 600 m/s with charge of 20 uC enters a magnetic field of 1.6 T and reases at a ced in the is swept into a circular arc of radius 225 m. o Show that the mass of the particle is 12 milligrams. 1 0 25-27. A current of 10.0 A flows through a rod of length 0.20 m placed perpendicularly across a magnetic field of 0.050 T. Show that the magnetic force on the rod is 0.10 N.omie , 160
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