25.00 mL of a solution containing KIO4 is treated with excess potassium iodide. IO4- + 8H+ + 7I- → 4I2 + 4H2O The resulting solution is titrated with 0.15 M sodium thiosulfate pentahydrate. The average titre was 21.76 mL. I2 + 2S2O32- → 2I- + S4O62- What mass of KIO4 (in g) was dissolved in water to make the original solution?

25.00 mL of a solution containing KIO4 is treated with excess potassium iodide. IO4- + 8H+ + 7I- → 4I2 + 4H2O The resulting solution is titrated with 0.15 M sodium thiosulfate pentahydrate. The average titre was 21.76 mL. I2 + 2S2O32- → 2I- + S4O62- What mass of KIO4 (in g) was dissolved in water to make the original solution?

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.35QAP

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The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities of the following compounds in grams per 100 mL of water. Because these compounds are only slightly soluble, assume that the volume does not change on dissolution and calculate the solubility product for each. (a) BaSiF6, 0.026 g/100 mL (contains SiF62- ions) (b) Ce(IO3)4, 1.5102 g/100 mL (c) Gd2(SO4)3, 3.98 g/100 mL (d) (NH4)2PtBr6, 0.59 g/100 mL (contains PtBr62- ions)
A 75.0 mL solution of potassium iodate (KIO3, 214.0 g/mol, 98%) was treated with KI and H2SO4 and then titrated with sodium thiosulfate (Na2S2O3, 158.1 g/mol). The titration required 5.00 mL of the titrant. If the solution contained 0.0325 g of the primary standard, what is the concentration of the titrant?
For breakfast, the nihilistic Rick Sanchez ate 100 g of cereal mixed with 20 g of milk. A 1.500 g sample of the same cereal was analyzed using the Kjeldahl method, and the liberated NH3 was distilled into 50 mL of a 0.0227 M HCl solution, and back-titrated with 2.85 mL of 0.0112 M NaOH solution. A 1.100 g sample of milk was also analyzed, and the liberated NH3 was distilled into 55 mL of a 0.0234 M HCl solution, and back-titrated with a 3.10 mL of 0.0121 M NaOH. Use the values: MM N=14.07 g/mol. meat= 6.25 dairy= 6.38 cereal= 5.70 What is the % protein in the cereal sample? What is the % protein in the milk sample?
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