28. A student attempts to lift a uniform 3.4-kg beam off the floor and raise it to a vertical position. The beam is about to slide at this instant as shown in the diagram. Fr 78° 38 a) Find the magnitude of the force Fp. 13 N b) Find the magnitude and direction of the force exerted by the floor on the beam. 67°(ccw From f10or)

28. A student attempts to lift a uniform 3.4-kg beam off the floor and raise it to a vertical position. The beam is about to slide at this instant as shown in the diagram. Fr 78° 38 a) Find the magnitude of the force Fp. 13 N b) Find the magnitude and direction of the force exerted by the floor on the beam. 67°(ccw From f10or)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter5: More Applications Of Newton’s Laws

Section: Chapter Questions

Problem 6P: The person in Figure P5.6 weighs 170 lb. As seen from the front, each light crutch makes an angle of...

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Find the tension in each of the three cables supporting the traffic light if it weighs
The person in Figure P5.6 weighs 170 lb. As seen from the front, each light crutch makes an angle of 22.0 with the vertical. Half of the persons weight is supported by the crutches. The other half is supported by the vertical forces of the ground on the persons feet. Assuming that the person is moving with constant velocity and the force exerted by the ground on the crutches acts along the crutches, determine (a) the smallest possible coefficient of friction between crutches and ground and (b) the magnitude of the compression force in each crutch. Figure P5.6
The board sandwiched between two other boards in Figure P5.97 weighs 95.5 N. If the coefficient of static friction between the boards is 0.663, what must be the magnitude of the compression forces (assumed horizontal) acting on both sides of the center board to keep it from slipping?
The person in Figure P4.49 weighs 170. lb. Eachcrutch makes an angle of 22.0° with the vertical (as seen from thefront). Half of the person’s weight is supported by the crutches,the other half by the vertical forces exerted by the ground on his feet. Assuming he is atrest and the force exerted bythe ground on the crutchesacts along the crutches, determine(a) the smallest possiblecoefficient of friction betweencrutches and ground and(b) the magnitude of the compressionforce supported byeach crutch.
A persons head is bent over a book. The head weighs P=37.2 N and is supported by the muscle force Fm exerted by the neck extensor muscles and by the contact force Fc excerted at the atlantooccipital joint. Given that the magnitude of Fm is 60.0 N and is directed 35.0 degree below the horizontal. Find the direction of the contact force Fc. If the direction is below the horizontal, enter a negative value.
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Determine the tension in the rope and the acceleration of each block. Answer: 40.95 N, 0.28 m/s^2, 0.43 m/s^2
2) A student’s head is bent over her physics book. The head weighs P = 24.6 N and is supported by the muscle force F→mF→m exerted by the neck extensor muscles and by the contact force F→cF→c exerted at the atlantooccipital joint. Given that the magnitude of F→mF→m is 60.0 N and is directed 35.0° below the horizontal. a.) Find the magnitude of the contact force F→cF→c . b.)Find the direction of the contact force Fc−→Fc→ . If the direction is below the horizontal, enter a negative value.
What horizontal force must be applied to a 2150 N boulder to achieve horizontal acceleration of 15.0m/s^2?
** I am confused on this being below the horizontal. Is that making Fy a negative? If so, would that then affect the calculation for normal force? A box (M = 4 kg) is resting on a frictionless horizontal surface. Then there is a 25 Newton force acting onit at an angle 35 degrees below the horizontal.1. Find the horizontal component of the force, Fx - I have Fcostheta so 25cos35 = 20.479 N2. Find the vertical component of the force, Fy - I don't know if this should be 25sin35 or 25sin(-35) 3. Find the normal force acting on the box - Fn = mg - Fy (but I do not understand if this is going to be a positive or negative Fy, obviously negative would make this mg + Fy)4. Find the acceleration of the box5. Find the distance it will travel in 3 seconds.
A 155-N bird feeder is supported by three cables. Find the tension in the cable attached at 60°. (Report answer to 3SF; unit: N)
A traffic light with a weight of 122 N is suspended from a support with cables, making angles of 37° and 530° with the horizontal as shown in the figure. According to this; 15 - Calculate the value of ǀ T1 + T2ǀ according to the figure. A) 122 N B) 79,9 N C) 75,1 N D) 73,3 N E) 60,1 N