28.29 Two long, parallel wires are separated by a dis- tance of 0.400 m (Fig. E28.29). The currents ₁ and 1₂ have the directions shown. (a) Calculate the magnitude of the force ex- erted by each wire on a 1.20 m length of the other. Is the force attractive or repulsive? (b) Each current is doubled, so that I₁ becomes 10.0 A and I₂ becomes 4.00 A. Now what is the magnitude of the force that each wire exerts on a 1.20 m length of the other? Figure E28.29 1₁ = 5.00 A 0.400 m ✓ 1₂ = 2.00 A

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter24: Electromagnetic Waves
Section24.1: Displacement Current And The Generalized Form Of Ampère’s Law
Problem 24.1QQ
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28.29 Two long, parallel
wires are separated by a dis-
tance of 0.400 m (Fig. E28.29).
The currents 1₁ and 1₂ have the
directions shown. (a) Calculate
the magnitude of the force ex-
erted by each wire on a 1.20 m
length of the other. Is the force
attractive or repulsive? (b) Each
current is doubled, so that I₁ becomes 10.0 A and I₂ becomes 4.00 A.
Now what is the magnitude of the force that each wire exerts on a
1.20 m length of the other?
Figure E28.29
₁
5.00 A
0.400 m
1₂ =
=
2.00 A
||
Transcribed Image Text:28.29 Two long, parallel wires are separated by a dis- tance of 0.400 m (Fig. E28.29). The currents 1₁ and 1₂ have the directions shown. (a) Calculate the magnitude of the force ex- erted by each wire on a 1.20 m length of the other. Is the force attractive or repulsive? (b) Each current is doubled, so that I₁ becomes 10.0 A and I₂ becomes 4.00 A. Now what is the magnitude of the force that each wire exerts on a 1.20 m length of the other? Figure E28.29 ₁ 5.00 A 0.400 m 1₂ = = 2.00 A ||
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