29 From the given information below, which expression gives the correct value in determining the standard enthalpy change of combustion for liquid benzene (C6H6) in KJ/mole? * A Delta H of formation of Oxygen gas is zero. Consider the following information. Compound CH(1) CO,(g) H,O(1) AH /kJ mol +394 -286 +49 CH(1) + 70;(g) → 6CO(g) + H,O(1) O 12(-394) + (-286) + 2(49) O 12(394) + 6(286) - 2(-49) O 6(-394) + 3(286) - (-49) O 6(394) + 3(286) - (-49)

Chemistry: An Atoms First Approach
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Chapter7: Chemical Energy
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Problem 61E: A coffee-cup calorimeter initially contains 125 g water at 24.2C. Potassium bromide (10.5 g), also...
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From the given information below, which expression gives the correct value in determining the
standard enthalpy change of combustion for liquid benzene (C6H6) in KJ/mole? * .
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Delta H of formation of Oxygen gas is zero.
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Consider the following information.
Calls
Compound
CH(1)
CO(g)
H,O(1)
Files
AH / kJ mol
+394
+49
-286
CÇHe(1) + 702(g)→ 6CO,(g) + H0(1)
12(-394) + (-286) + 2(49)
12(394) + 6(286) – 2(-49)
6(-394) + 3(286) – (-49)
6(394) + 3(286) – (-49)
00
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Transcribed Image Text:< > Q Search Close Activity Chat 29 Teams From the given information below, which expression gives the correct value in determining the standard enthalpy change of combustion for liquid benzene (C6H6) in KJ/mole? * . Assignments Delta H of formation of Oxygen gas is zero. Calendar Consider the following information. Calls Compound CH(1) CO(g) H,O(1) Files AH / kJ mol +394 +49 -286 CÇHe(1) + 702(g)→ 6CO,(g) + H0(1) 12(-394) + (-286) + 2(49) 12(394) + 6(286) – 2(-49) 6(-394) + 3(286) – (-49) 6(394) + 3(286) – (-49) 00 Apps (? Help >> 1:57 PM Desktop 12/13/2021
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