2Br + 2K* → Br₂ + 2K MM of K-39.10 g/mol MM of Br₂159.8 g/mol R=8.314 J/mol-K F-96,485 J/mol-V 4.77 g 9.54 g 1.17 g 2.33 g

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 128AE: It took 150. s for a current of 1.25 A to plate out 0.109 g of a metal from a solution containing...
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A current of 0.800 A is passed through an electrolytic cell containing molten KBr for
2.00 h. How much product will be formed at the anode?
2Br + 2K → Br₂ + 2K
MM of K-39.10 g/mol
MM of Br₂ = 159.8 g/mol
R= 8.314 J/mol-K
F=96,485 J/mol-V
4.77 g
09.54 g
01.17 g
2.33 g
Transcribed Image Text:A current of 0.800 A is passed through an electrolytic cell containing molten KBr for 2.00 h. How much product will be formed at the anode? 2Br + 2K → Br₂ + 2K MM of K-39.10 g/mol MM of Br₂ = 159.8 g/mol R= 8.314 J/mol-K F=96,485 J/mol-V 4.77 g 09.54 g 01.17 g 2.33 g
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